Nursing Elites

1. A male patient is being treated with testosterone gel for hypogonadism. What important instruction should the nurse provide?

• A. Apply the gel to the face and neck for maximum absorption.
• B. Apply the gel to the chest or upper arms and allow it to dry completely before dressing.
• C. Apply the gel to the scalp and back.
• D. Apply the gel to the genitals for improved results.

Correct answer: B

Rationale: The correct instruction for applying testosterone gel is to apply it to the chest or upper arms and allow it to dry completely before dressing. This is important to prevent the transfer of the medication to others. Applying it to the face and neck (Choice A) is incorrect as these areas are not recommended. Similarly, applying it to the scalp and back (Choice C) or the genitals (Choice D) is also incorrect and can lead to inappropriate absorption or undesirable effects.

2. Which of the following mediators of inflammation causes increased capillary permeability and pain?

• A. Serotonin
• B. Histamine
• C. Bradykinin
• D. Nitric oxide

Correct answer: C

Rationale: Bradykinin is the correct answer. It is a potent mediator of inflammation that causes increased capillary permeability and is responsible for the pain associated with inflammation. Serotonin and histamine are also mediators of inflammation, but they are not primarily known for increasing capillary permeability or inducing pain. Nitric oxide is involved in various physiological processes but is not a primary mediator of inflammation that causes increased capillary permeability and pain.

3. When planning care for a cardiac patient, the nurse knows that in response to an increased workload, cardiac myocardial cells will:

• A. Increase in size
• B. Decrease in length
• C. Increase in excitability
• D. Increase in number

Correct answer: A

Rationale: The correct answer is A: Increase in size. Cardiac hypertrophy occurs when myocardial cells increase in size to compensate for an increased workload. This adaptation allows the heart to pump more effectively. Choice B, Decrease in length, is incorrect as cardiac cells do not decrease in length in response to increased workload. Choice C, Increase in excitability, is incorrect as increased workload does not lead to an increase in excitability of cardiac cells. Choice D, Increase in number, is incorrect as cardiac cells do not increase in number but rather increase in size to handle the increased workload.

4. A patient presents with a rash from poison ivy. The nurse knows that this is which type of hypersensitivity?

• A. Type I
• B. Type II
• C. Type III
• D. Type IV

Correct answer: D

Rationale: A rash from poison ivy is an example of a type IV hypersensitivity reaction. Type IV hypersensitivity reactions are delayed cell-mediated immune responses involving T cells. This type of reaction is characterized by a delayed onset, typically occurring 48-72 hours after exposure to the antigen. Choice A, Type I hypersensitivity reactions, are immediate hypersensitivity reactions mediated by IgE antibodies. Choices B and C, Type II and Type III hypersensitivity reactions, involve antibody-mediated cytotoxicity and immune complex deposition, respectively, which are not characteristic of poison ivy-induced rashes.

5. The patient should be taught that an improvement in symptoms will likely be noticed within

• A. 48 hours.
• B. a week to 10 days.
• C. 2 to 3 weeks.
• D. 4 to 6 weeks.

Correct answer: C

Rationale: When taking isoniazid and rifampin for active tuberculosis, patients should be taught that an improvement in symptoms will likely be noticed within 2 to 3 weeks. Choice A (48 hours) is too soon to expect significant improvement in symptoms. Choice B (a week to 10 days) is also too early for noticeable improvement with this medication regimen. Choice D (4 to 6 weeks) is too far out to expect a noticeable improvement in symptoms.

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