Nursing Elites

1. Anemia of chronic inflammation is generally classified as:

• A. Hypochromic and microcytic.
• B. Hypochromic and macrocytic.
• C. Normochromic and microcytic.
• D. Normochromic and normocytic.

Correct answer: D

Rationale: Anemia of chronic inflammation is typically characterized by normochromic (normal hemoglobin content) and normocytic (normal cell size) red blood cells. Choice A, hypochromic and microcytic, is incorrect because hypochromic refers to reduced hemoglobin content and microcytic refers to smaller than normal red blood cells, which are not typically seen in anemia of chronic inflammation. Choice B, hypochromic and macrocytic, is also incorrect as macrocytic refers to larger than normal red blood cells. Choice C, normochromic and microcytic, is incorrect because microcytic red blood cells are smaller than normal. Therefore, the correct classification for anemia of chronic inflammation is normochromic and normocytic.

2. A patient has been prescribed sildenafil (Viagra) for erectile dysfunction. What important information should the healthcare provider provide?

• A. This medication can cause sudden hearing loss.
• B. This medication should not be taken more than once a day.
• C. You should avoid taking this medication with high-fat meals.
• D. Avoid taking nitrates while on this medication.

Correct answer: D

Rationale: The correct answer is D. Sildenafil (Viagra) should not be taken with nitrates due to the risk of severe hypotension. Nitrates can potentiate the hypotensive effects of sildenafil, leading to a dangerous drop in blood pressure. Choice A is incorrect because sudden hearing loss is a rare but serious side effect associated with sildenafil, not a common side effect. Choice B is not the most important information related to sildenafil use. While it is generally recommended not to exceed one dose per day, the interaction with nitrates is more critical. Choice C is also important to consider as high-fat meals can delay the onset of action of sildenafil, but it is not as crucial as avoiding nitrates.

3. What is the expected outcome of administering a granulocyte colony-stimulating factor (G-CSF)?

• A. Reduction in red blood cell count
• B. Decreased number of infections
• C. Decreased fatigue and increased energy
• D. Increase in white blood cell count

Correct answer: B

Rationale: The correct answer is B: Decreased number of infections. Granulocyte colony-stimulating factor (G-CSF) is a medication used to stimulate the production of white blood cells, specifically granulocytes, in the body. By increasing the number of white blood cells, G-CSF helps in boosting the immune system, leading to a decreased number of infections. Choice A is incorrect as G-CSF does not cause a reduction in red blood cell count. Choice C is incorrect as G-CSF primarily affects white blood cells and is not directly related to fatigue or energy levels. Choice D is incorrect as G-CSF does increase the white blood cell count but does not usually elevate it to 20,000 mm3.

4. A client with a history of chronic alcoholism presents to the emergency department with a complaint of double vision. Which cranial nerve is most likely involved?

• A. Cranial nerve I (Olfactory)
• B. Cranial nerve III (Oculomotor)
• C. Cranial nerve VI (Abducens)
• D. Cranial nerve VII (Facial)

Correct answer: C

Rationale: The correct answer is Cranial nerve VI (Abducens). Chronic alcoholism can lead to damage to the abducens nerve, which controls the lateral movement of the eye. This damage can result in symptoms like double vision. Cranial nerve I (Olfactory) is responsible for the sense of smell and is not related to eye movement. Cranial nerve III (Oculomotor) controls most of the eye movements but is less likely to be affected in chronic alcoholism than the abducens nerve. Cranial nerve VII (Facial) is responsible for facial movements and is not associated with double vision.

5. A 20-year-old college student has presented to her campus medical clinic for a scheduled Pap smear. The clinician who will interpret the smear will examine cell samples for evidence of:

• A. Changes in cell shape, size, and organization
• B. Presence of unexpected cell types
• C. Ischemic changes in cell sample
• D. Abnormally high numbers of cells

Correct answer: A

Rationale: The correct answer is changes in cell shape, size, and organization (Choice A). Pap smears are performed to detect potential precancerous or cancerous conditions by examining the cells for any abnormalities in their shape, size, or organization. This helps in identifying early signs of cervical cancer. Choices B, C, and D are incorrect because Pap smears primarily focus on detecting cellular changes associated with cancer, not unexpected cell types, ischemic changes, or abnormally high numbers of cells.

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