Nursing Elites

1. You are performing an admission assessment on an older adult patient newly admitted for end-stage liver disease. What principle should guide your assessment of the patient's skin turgor?

• A. Overhydration is common among healthy older adults.
• B. Dehydration causes the skin to appear spongy.
• C. Inelastic skin turgor is a normal part of aging.
• D. Skin turgor cannot be assessed in patients over 70.

Correct answer: C

Rationale: Inelastic skin is a normal change of aging. However, this does not mean that skin turgor cannot be assessed in older patients. Dehydration, not overhydration, causes inelastic skin with tenting. Overhydration, not dehydration, causes the skin to appear edematous and spongy. Choice A is incorrect because overhydration is not common among healthy older adults. Choice B is incorrect because dehydration leads to inelastic skin, not sponginess. Choice D is incorrect as skin turgor assessment can be done in patients of any age, including those over 70.

2. The triage nurse notes upon assessment in the emergency room that the patient with anxiety is hyperventilating. The nurse is aware that hyperventilation is the most common cause of which acid-base imbalance?

• A. Respiratory acidosis
• B. Respiratory alkalosis
• C. Metabolic acidosis
• D. Metabolic alkalosis

Correct answer: B

Rationale: The correct answer is B: Respiratory alkalosis. Hyperventilation is the most common cause of acute respiratory alkalosis. When a patient hyperventilates due to anxiety or other causes, they blow off excessive carbon dioxide, leading to a decrease in PaCO2 and a rise in pH. Choices A, C, and D are incorrect because hyperventilation leads to a decrease in PaCO2, causing respiratory alkalosis, not respiratory acidosis, metabolic acidosis, or metabolic alkalosis.

3. You are performing an admission assessment on an older adult patient newly admitted for end-stage liver disease. What principle should guide your assessment of the patients skin turgor?

• A. Overhydration is common among healthy older adults.
• B. Dehydration causes the skin to appear spongy
• C. Inelastic skin turgor is a normal part of aging
• D. Skin turgor cannot be assessed in patients over 70.

Correct answer: C

Rationale:

4. You are an emergency-room nurse caring for a trauma patient. Your patient has the following arterial blood gas results: pH 7.26, PaCO2 28, HCO3 11 mEq/L. How would you interpret these results?

• A. Respiratory acidosis with no compensation
• B. Metabolic alkalosis with a compensatory alkalosis
• C. Metabolic acidosis with no compensation
• D. Metabolic acidosis with a compensatory respiratory alkalosis

Correct answer: D

Rationale: A low pH indicates acidosis (normal pH is 7.35 to 7.45). The PaCO2 is also low, which causes alkalosis. The bicarbonate is low, which causes acidosis. The pH bicarbonate more closely corresponds with a decrease in pH, making the metabolic component the primary problem. Therefore, the correct interpretation of the arterial blood gas results is metabolic acidosis with a compensatory respiratory alkalosis. Choices A, B, and C are incorrect because they do not accurately reflect the primary acid-base disturbance and the compensatory response seen in the given results.

5. Who would have the greatest percentage of body water?

• A. an obese male
• B. a nonobese male
• C. a nonobese female
• D. a newborn

Correct answer: D

Rationale: Newborns have a higher percentage of body water compared to adults due to their higher body fluid content. Factors such as the higher ratio of body surface area to body volume and lower body fat content contribute to this. This is why a newborn would have the greatest percentage of body water. Choices A, B, and C are incorrect because obesity and gender do not determine the percentage of body water in individuals. Therefore, the correct answer is a newborn.

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