Nursing Elites

1. The nurse is caring for a client with multiple myeloma and is monitoring the client for signs of hypercalcemia. Which symptom would be an early indication?

• A. Polyuria
• B. Polyphagia
• C. Polydipsia
• D. Weight loss

Correct answer: A

Rationale: In patients with multiple myeloma, hypercalcemia is a common complication due to the release of calcium from the bones as a result of osteolytic lesions. One of the early symptoms of hypercalcemia is polyuria, or increased urine output. This occurs because elevated calcium levels can lead to impaired renal function and increased renal excretion of calcium, which results in increased urine production. Early recognition of polyuria can help prompt further evaluation and management of hypercalcemia, as untreated hypercalcemia can lead to more severe complications.

2. An oncology patient has just returned from the post-anesthesia care unit after an open hemicolectomy. This patient’s plan of nursing care should prioritize which of the following?

• A. Assess the patient hourly for signs of compartment syndrome.
• B. Assess the patient’s fine motor skills once per shift.
• C. Assess the patient’s wound for dehiscence every 4 hours.
• D. Maintain the patient’s head of bed at 45 degrees or more at all times.

Correct answer: C

Rationale: After an open hemicolectomy (surgical removal of part of the colon), monitoring the surgical wound for signs of dehiscence (wound reopening) is a critical nursing priority. Dehiscence is a serious postoperative complication that can occur if the surgical site does not heal properly. Regular wound assessments every 4 hours allow the nurse to identify early signs of complications, such as redness, swelling, increased drainage, or separation of the wound edges. Early detection is key to preventing further complications, such as infection or evisceration (protrusion of abdominal organs through the wound).

3. A client with neutropenia is admitted to the hospital. What precaution is most important for the nurse to implement?

• A. Strict hand hygiene.
• B. Limit visitor contact with the client.
• C. Administer prophylactic antibiotics as ordered.
• D. Administer blood products as ordered.

Correct answer: A

Rationale: The correct answer is A: Strict hand hygiene. Neutropenic clients have a low level of neutrophils, which are important in fighting infections. Therefore, maintaining strict hand hygiene is crucial in preventing the introduction of pathogens that could lead to infections. Limiting visitor contact (choice B) is important but not as critical as preventing the introduction of pathogens through proper hand hygiene. Administering prophylactic antibiotics (choice C) and blood products (choice D) are treatment measures and do not address the preventive aspect that hand hygiene provides.

4. While a patient is receiving IV doxorubicin hydrochloride for the treatment of cancer, the nurse observes swelling and pain at the IV site. The nurse should prioritize what action?

• A. Stopping the administration of the drug immediately
• B. Notifying the patient's physician
• C. Continuing the infusion but decreasing the rate
• D. Applying a warm compress to the infusion site

Correct answer: A

Rationale: The correct action for the nurse to take when observing swelling and pain at the IV site during the administration of doxorubicin hydrochloride is to stop the administration of the drug immediately. Doxorubicin hydrochloride can cause severe tissue damage, so discontinuing the infusion is crucial to prevent further harm to the patient. Notifying the physician is important, but it should not take precedence over stopping the drug. Continuing the infusion, even at a decreased rate, can exacerbate tissue damage. Applying a warm compress is not appropriate in this situation and may worsen the tissue injury caused by the drug.

5. The cells of a normal individual can replicate in a specified rate. If the rate of replication becomes uncontrollable, which of the following is lacking from the patient?

• A. Apoptosis
• B. Contact inhibition
• C. Stable cells
• D. Labile cells

Correct answer: B

Rationale: Contact inhibition is a regulatory mechanism that prevents cells from proliferating once they reach a certain density. Normally, when cells grow and touch each other (such as in a monolayer), they stop dividing, maintaining tissue integrity and structure. When contact inhibition is lacking, as in many cancerous cells, cells continue to grow and divide uncontrollably, leading to tumor formation. This loss of regulation is a hallmark of cancerous growth.

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