Nursing Elites

1. A patient is found to have liver disease, resulting in the removal of a lobe of his liver. Adaptation to the reduced size of the liver leads to ___________ of the remaining liver cells.

• A. Metaplasia
• B. Organ atrophy
• C. Compensatory hyperplasia
• D. Physiologic hyperplasia

Correct answer: C

Rationale: Compensatory hyperplasia is the process by which the remaining cells increase in number to adapt to the reduced size of the liver. In this case, after the removal of a lobe of the liver, the remaining cells undergo compensatory hyperplasia to compensate for the lost tissue. Metaplasia refers to the reversible change of one cell type to another, not an increase in cell number. Organ atrophy is the decrease in organ size due to cell shrinkage or loss, which is opposite to an increase in cell number seen in compensatory hyperplasia. Physiologic hyperplasia is the increase in cell number in response to a normal physiological demand, not specifically due to the removal of a portion of the organ.

2. A client with amyotrophic lateral sclerosis (ALS) is admitted to the hospital. Which intervention should the nurse include in the plan of care?

• A. Administer muscle relaxants as prescribed.
• B. Assist the client with activities of daily living (ADLs).
• C. Provide nutritional support to prevent aspiration.
• D. Encourage the client to participate in physical therapy.

Correct answer: C

Rationale: The correct intervention for a client with ALS is to provide nutritional support to prevent aspiration. ALS causes muscle weakness, including the muscles used for swallowing, increasing the risk of aspiration. Providing proper nutrition and support can help prevent this complication. Administering muscle relaxants (Choice A) may not be suitable for ALS as it can further weaken muscles. While assisting with ADLs (Choice B) and encouraging physical therapy (Choice D) are important aspects of care, the priority for a client with ALS is to prevent complications related to swallowing and nutrition.

3. Which patient is most likely to be diagnosed with complex regional pain syndrome II (CRPS II)?

• A. A patient who has experienced a spinal cord injury and reports severe, burning pain in his legs.
• B. A patient who reports severe pain in her hand following a surgery for carpal tunnel syndrome.
• C. A patient who develops pain in his foot following a fracture and immobilization with a cast.
• D. A patient who experiences chronic pain and swelling in his arm following a brachial plexus injury.

Correct answer: D

Rationale: Complex regional pain syndrome II (CRPS II) typically occurs after an injury to a peripheral nerve. In this case, a brachial plexus injury involves damage to the nerves that control muscles in the arm and hand, leading to chronic pain and swelling. Choices A, B, and C describe pain related to other conditions such as spinal cord injury, carpal tunnel surgery, and fracture immobilization, which are not typically associated with CRPS II.

4. Which of the following describes the condition in the body of clients experiencing hypovolemia?

• A. Increased urine retention
• B. Insufficient circulating blood volume
• C. Bounding peripheral pulses
• D. Crackles auscultated in the lungs

Correct answer: B

Rationale: The correct answer is B: Insufficient circulating blood volume. Hypovolemia is a condition characterized by a decrease in the volume of blood plasma. This reduction in circulating blood volume can lead to inadequate perfusion of tissues and organs, potentially resulting in shock if left untreated. Choices A, C, and D are incorrect because increased urine retention, bounding peripheral pulses, and crackles auscultated in the lungs are not typical manifestations of hypovolemia.

5. A patient has been prescribed mifepristone (RU-486) to terminate a pregnancy. How does this drug achieve its therapeutic effect?

• A. By inhibiting the action of progesterone, which is necessary to maintain pregnancy.
• B. By increasing estrogen levels, which induce uterine contractions.
• C. By altering the uterine lining, preventing implantation.
• D. By stimulating uterine contractions, which expel the embryo.

Correct answer: A

Rationale: Mifepristone (RU-486) functions by inhibiting the action of progesterone, a hormone crucial for maintaining pregnancy. By blocking progesterone, mifepristone disrupts the uterine environment necessary for pregnancy continuation, ultimately leading to termination. Choice B is incorrect because mifepristone does not increase estrogen levels; instead, it acts on progesterone. Choice C is incorrect as mifepristone's mechanism does not involve altering the uterine lining to prevent implantation. Choice D is incorrect because mifepristone does not directly stimulate uterine contractions; its primary action is through progesterone inhibition.

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