Nursing Elites

1. A client's arterial blood gas results show a pH of 7.3 and a PaCO2 of 50 mm Hg. The client is experiencing which of the following acid-base imbalances?

• A. Metabolic acidosis
• B. Metabolic alkalosis
• C. Respiratory acidosis
• D. Respiratory alkalosis

Correct answer: C

Rationale: In respiratory acidosis, there is an excess of carbon dioxide (PaCO2 > 45 mm Hg) leading to a decrease in pH (<7.35). The given values of a pH of 7.3 and PaCO2 of 50 mm Hg indicate respiratory acidosis. Metabolic acidosis involves a primary decrease in bicarbonate levels with a compensatory decrease in PaCO2 to maintain balance. Metabolic alkalosis is characterized by elevated pH and bicarbonate levels. Respiratory alkalosis is marked by low PaCO2 and increased pH levels.

2. How does the pain of a myocardial infarction (MI) differ from stable angina?

• A. Accompanied by shortness of breath
• B. Feelings of fear or anxiety
• C. Lasts about 3-5 minutes
• D. Relieved by taking nitroglycerin

Correct answer: A

Rationale: The pain of an MI is often accompanied by shortness of breath and feelings of fear or anxiety. It typically lasts longer than 15 minutes and is not relieved by nitroglycerin. Unlike stable angina, the pain of an MI occurs without a known cause such as exertion.

3. A client is being admitted to the surgical unit from the PACU following a cholecystectomy. Which of the following assessments is the nurse's priority?

• A. Bowel sounds
• B. Surgical dressing
• C. Temperature
• D. Oxygen saturation

Correct answer: D

Rationale: The priority assessment for a client being admitted to the surgical unit following a cholecystectomy is oxygen saturation. Monitoring oxygen saturation is crucial to ensure adequate oxygenation and ventilation, especially after surgery. Hypoxia can have serious consequences and needs to be promptly addressed. While assessing bowel sounds, surgical dressing, and temperature are important, oxygen saturation takes precedence in this situation.

4. A client with a long history of smoking is being assessed by a nurse. Which finding is a common complication of chronic obstructive pulmonary disease (COPD)?

• A. Decreased anteroposterior chest diameter
• B. Increased breath sounds
• C. Prolonged expiratory phase
• D. Increased chest expansion

Correct answer: C

Rationale: In COPD, a prolonged expiratory phase is a typical finding caused by airway obstruction and air trapping. This results in difficulty expelling air from the lungs, leading to the characteristic prolonged exhalation in individuals with COPD.

5. When admitting a client with active tuberculosis to a room on a medical-surgical unit, which of the following room assignments should the nurse make?

• A. A room with air exhaust directly to the outdoor environment
• B. A room with another nonsurgical client
• C. A room in the ICU
• D. A room that is within view of the nurses' station

Correct answer: A

Rationale: When admitting a client with active tuberculosis, it is crucial to assign them to a room with air exhaust directly to the outdoor environment to prevent the spread of infectious particles to other patients and healthcare workers. This setup helps in reducing the risk of transmission within the healthcare facility. Placing the client in a room with another nonsurgical client or in the ICU may increase the chances of spreading the infection. Additionally, placing the client in a room within view of the nurses' station does not address the need for proper ventilation to minimize transmission of tuberculosis.

Similar Questions