a 20 year old college student has presented to her campus medical clinic for a scheduled pap smear the clinician who will interpret the smear will exa
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ATI RN

Final Exam Pathophysiology

1. A 20-year-old college student has presented to her campus medical clinic for a scheduled Pap smear. The clinician who will interpret the smear will examine cell samples for evidence of:

Correct answer: A

Rationale: The correct answer is changes in cell shape, size, and organization (Choice A). Pap smears are performed to detect potential precancerous or cancerous conditions by examining the cells for any abnormalities in their shape, size, or organization. This helps in identifying early signs of cervical cancer. Choices B, C, and D are incorrect because Pap smears primarily focus on detecting cellular changes associated with cancer, not unexpected cell types, ischemic changes, or abnormally high numbers of cells.

2. A 60-year-old man presents with painless hematuria. Which of the following should be the next step in the evaluation?

Correct answer: C

Rationale: In a 60-year-old man presenting with painless hematuria, the next step in the evaluation should be cystoscopy. Cystoscopy is recommended to assess the cause of hematuria, particularly to rule out bladder cancer, which is more common in older individuals. Urinalysis (Choice A) can provide initial information but may not definitively diagnose the underlying cause. Renal ultrasound (Choice B) and intravenous pyelogram (Choice D) are imaging studies that may be considered later in the evaluation process but are not the initial step for painless hematuria.

3. A 57-year-old male presents to his primary care provider with a red face, hands, feet, ears, headache, and drowsiness. A blood smear reveals an increased number of erythrocytes, indicating:

Correct answer: D

Rationale: In this case, the symptoms of a red face, hands, feet, ears, headache, and drowsiness along with an increased number of erythrocytes in the blood smear are indicative of polycythemia vera. This condition is characterized by the overproduction of red blood cells, leading to symptoms related to increased blood volume and viscosity. Leukemia (Choice A) is a cancer of the blood and bone marrow, but the presentation described here is more suggestive of polycythemia vera. Sideroblastic anemia (Choice B) is characterized by abnormal iron deposits in erythroblasts, not an increased number of erythrocytes. Hemosiderosis (Choice C) refers to abnormal accumulation of iron in the body, not an increase in red blood cells as seen in polycythemia vera.

4. A report comes back indicating that muscular atrophy has occurred. A nurse recalls that muscular atrophy involves a decrease in muscle cell size:

Correct answer: B

Rationale: The correct answer is B: Size. Muscular atrophy is characterized by a reduction in the size of muscle cells. This decrease in size can be due to various factors such as disuse, aging, or disease. Choice A, Number, is incorrect because muscular atrophy does not involve a decrease in the number of muscle cells but rather their size. Choice C, Vacuoles, is incorrect as vacuoles are not directly related to the definition of muscular atrophy. Choice D, Lipofuscin, is incorrect as lipofuscin is a pigment associated with aging and has no direct connection to the decrease in muscle cell size seen in muscular atrophy.

5. What condition can be caused by an excessive amount of growth hormone released by the pituitary gland in childhood?

Correct answer: B

Rationale: Gigantism is the correct answer. It is a condition caused by excessive growth hormone release before the epiphyseal plates close, leading to abnormal growth. Acromegaly (choice A) is caused by excess growth hormone after the epiphyseal plates close, resulting in enlargement of bones and tissues. Syndrome of inappropriate antidiuretic hormone (choice C) is characterized by the excessive release of antidiuretic hormone, leading to water retention and dilutional hyponatremia. Dwarfism (choice D) is a condition characterized by significantly below-average height.

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