ATI RN
Pathophysiology Final Exam
1. What is the primary therapeutic action of tamsulosin (Flomax) in a male patient with benign prostatic hyperplasia (BPH)?
- A. Relaxation of the muscles in the prostate and bladder neck, leading to improved urinary flow.
- B. Reduction in prostate size and improvement in urinary symptoms.
- C. Increase in urine flow and relief of urinary obstruction.
- D. Improvement in erectile function.
Correct answer: A
Rationale: The correct answer is A: Relaxation of the muscles in the prostate and bladder neck, leading to improved urinary flow. Tamsulosin, a medication commonly prescribed for BPH, works by selectively blocking alpha-1 adrenergic receptors in the prostate, causing relaxation of smooth muscles in the prostate and bladder neck. This relaxation reduces the constriction in these areas, improving urinary flow and reducing symptoms such as hesitancy, urgency, frequency, and weak stream. Choice B is incorrect because tamsulosin does not directly reduce the size of the prostate. Choice C is incorrect as tamsulosin primarily acts by relaxing muscles rather than directly increasing urine flow. Choice D is incorrect as tamsulosin is not indicated for improving erectile function.
2. Medroxyprogesterone acetate (Provera) is indicated for the treatment of women with
- A. uterine bleeding.
- B. cervical cancer.
- C. ovarian cancer.
- D. fibromyalgia.
Correct answer: A
Rationale: Medroxyprogesterone acetate (Provera) is commonly used to treat conditions like abnormal uterine bleeding, amenorrhea, and endometriosis. It helps regulate the menstrual cycle and reduce excessive bleeding. Therefore, the correct answer is A. Choice B, cervical cancer, is incorrect because Provera is not indicated for the treatment of cancer. Choice C, ovarian cancer, is also incorrect as Provera is not a primary treatment for ovarian cancer. Choice D, fibromyalgia, is unrelated to the use of medroxyprogesterone acetate.
3. Which of the following birthmarks usually fade or regress as the child gets older?
- A. Hemangiomas
- B. Congenital dermal melanocytosis (i.e., Mongolian spots)
- C. Macular stains
- D. Hemangiomas, congenital dermal melanocytosis (i.e., Mongolian spots), and macular stains
Correct answer: D
Rationale: The correct answer is D. Hemangiomas, congenital dermal melanocytosis (i.e., Mongolian spots), and macular stains are birthmarks that usually fade or regress as the child gets older. Hemangiomas are vascular birthmarks that often shrink and fade over time. Congenital dermal melanocytosis (Mongolian spots) are blue-gray birthmarks commonly found on the lower back and buttocks of infants, which typically fade by adolescence. Macular stains, also known as salmon patches, are pink or red birthmarks that usually fade within the first few years of life. Choice D is correct because all the mentioned birthmarks tend to diminish as the child grows, unlike choices A, B, and C which do not fade or regress with age.
4. Which information would indicate more teaching is needed regarding hypersensitivity reactions? Type _______ hypersensitivity reactions involve an antibody response.
- A. I
- B. II
- C. III
- D. IV
Correct answer: D
Rationale: The correct answer is D: Type IV hypersensitivity reactions involve cell-mediated immunity, not an antibody response. This question tests knowledge of hypersensitivity reactions and their classification. Type I hypersensitivity reactions involve IgE antibodies, Type II involves IgG or IgM antibodies, and Type III involves immune complex deposition. Type IV hypersensitivity reactions are delayed and involve T cells, not antibodies. Therefore, if a person believes that Type IV hypersensitivity reactions involve an antibody response, more teaching is required.
5. Which of the following are normal arterial blood gas values?
- A. PH 7.25, PaCO2 52 mm Hg, PaO2 75 mm Hg, HCO3 18 mEq/L
- B. PH 7.50, PaCO2 30 mm Hg, PaO2 80 mm Hg, HCO3 28 mEq/L
- C. PH 7.40, PaCO2 40 mm Hg, PaO2 90 mm Hg, HCO3 24 mEq/L
- D. PH 7.15, PaCO2 30 mm Hg, PaO2 50 mm Hg, HCO3 24 mEq/L
Correct answer: C
Rationale: The correct answer is C: PH 7.40, PaCO2 40 mm Hg, PaO2 90 mm Hg, HCO3 24 mEq/L. These values represent a balanced state for arterial blood gas. Choice A has lower than normal PH and HCO3 levels and higher PaCO2 and lower PaO2 levels. Choice B has higher than normal PH and HCO3 levels, lower PaCO2, and a normal PaO2 level. Choice D has a significantly lower PH and PaO2 level, normal HCO3 level, and low PaCO2 level, indicating an acidic state with impaired oxygenation.
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