what is the numerical value of the roman number xvii
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HESI A2

Practice HESI A2 Math Test

1. What is the numerical value of the Roman numeral XVII?

Correct answer: B

Rationale: The Roman numeral XVII represents the number 17. In Roman numerals, X stands for 10 and V stands for 5. When V (5) is subtracted from X (10), it results in 5 being subtracted from 10, which equals 5. Adding this to V (5) gives the total value of XVII as 17. Choice A is incorrect because it is not the correct numerical value of XVII. Choice C and D are also incorrect as they do not correspond to the Roman numeral XVII.

2. Add 2\3 + 1\6 + 2\5.

Correct answer: A

Rationale: To add fractions, find a common denominator (30), which gives 20/30 + 5/30 + 12/30=37/30= 1 7/30

3. The metric system of measurement was developed in France during Napoleon's reign. It is based on what multiplication factor?

Correct answer: C

Rationale: The metric system is based on powers of 10, making calculations and conversions easier because each unit increases or decreases by a factor of 10.

4. A woman received a bottle of perfume as a present. The bottle contains 1/2 oz of perfume. How many milliliters is this?

Correct answer: A

Rationale: 1/2 oz of perfume is equal to approximately 15 mL. To convert ounces to milliliters, we need to know that 1 oz is approximately 30 mL. Therefore, half an ounce, which is 1/2 oz, would be half of 30 mL, which equals 15 mL. Choice B, 20 mL, is incorrect as it does not correspond to the conversion factor of 1 oz to 30 mL. Choice C, 10 mL, is incorrect as it is half of the actual value. Choice D, 50 mL, is incorrect as it is the value of 1 oz rather than half an ounce.

5. Subtract 28 3/4 - 5 5/6.

Correct answer: A

Rationale: To subtract mixed numbers, find a common denominator. Convert 28 3/4 to 28 9/12. Then, subtract 5 5/6 from 28 9/12 to get 22 11/12. Therefore, 28 3/4 - 5 5/6 = 22 & 11/12, which matches choice A. Choices B, C, and D are incorrect because they do not reflect the correct subtraction result after finding the common denominator and performing the subtraction.

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