Nursing Elites

1. A water fountain has a spherical base with a diameter of 50cm and a cylindrical body with a diameter of 30cm and a height of 80cm. What is the total surface area of the fountain (excluding the water surface)?

• A. 3142 sq cm
• B. 4712 sq cm
• C. 5486 sq cm
• D. 7957 sq cm

Correct answer: C

Rationale: To find the total surface area of the fountain, we first calculate the surface area of the sphere and the cylinder separately. For the sphere: - Radius = Diameter / 2 = 50 / 2 = 25 cm - Surface area of a sphere = 4πr² = 4 x π x 25² = 500π cm² For the cylinder: - Radius = Diameter / 2 = 30 / 2 = 15 cm - Surface area of a cylinder = 2πrh + 2πr² = 2 x π x 15 x 80 + 2 x π x 15² = 240π + 450π = 690π cm² Total surface area = Surface area of sphere + Surface area of cylinder = 500π + 690π = 1190π cm² ≈ 5486 sq cm. Therefore, the correct answer is C. Choice A (3142 sq cm) is incorrect as it is much smaller than the correct answer. Choices B and D are also incorrect as they do not reflect the accurate calculation of the total surface area of the fountain.

2. A lab needs 200ml of a 5% salt solution. They only have a 10% solution. How much 10% solution and water should be mixed?

• A. 100ml 10% solution, 100ml water
• B. 150ml 10% solution, 50ml water
• C. 160ml 10% solution, 40ml water
• D. 200ml 10% solution, 0ml water

Correct answer: B

Rationale: Rationale: 1. Let x be the volume of the 10% solution needed and y be the volume of water needed. 2. The total volume of the final solution is 200ml, so x + y = 200. 3. The concentration of the final solution is 5%, so the amount of salt in the final solution is 0.05 * 200 = 10g. 4. The amount of salt in the 10% solution is 0.1x, and the amount of salt in the water is 0, so the total amount of salt in the final solution is 0.1x. 5. Since the total amount of salt in the final solution is 10g, we have 0.1x = 10. 6. Solving for x, we get x = 100ml. 7. Substituting x =

3. The least common multiple (LCM) of two numbers is the smallest number that is a multiple of both. Which of the following represents the LCM of 14 and 21?

• A. 42
• B. 63
• C. 84
• D. 168

Correct answer: C

Rationale: Rationale: To find the least common multiple (LCM) of 14 and 21, we need to determine the smallest number that is a multiple of both 14 and 21. First, list the multiples of 14: 14, 28, 42, 56, 70, 84, ... Next, list the multiples of 21: 21, 42, 63, 84, ... The smallest number that appears in both lists is 42. Therefore, the LCM of 14 and 21 is 42.

4. In a scale drawing for a garden, 2 cm = 1 m. If the garden measures 8 cm by 10 cm in the drawing, how large will it be in reality?

• A. 2 m by 3 m
• B. 4 m by 5 m
• C. 8 m by 10 m
• D. 16 m by 20 m

Correct answer: C

Rationale: In the scale drawing, 2 cm represents 1 m. To find the actual dimensions of the garden in reality, we need to multiply the dimensions in the drawing by the scale factor. So, 8 cm x 2 = 16 cm in reality (length) and 10 cm x 2 = 20 cm in reality (width). Converting these to meters, the garden will be 16 m by 20 m. Choices A, B, and D are incorrect because they do not correctly apply the scale factor to determine the actual dimensions of the garden.

5. What is 80% of $500?

• A. $425
• B. $450
• C. $350
• D. $400

Correct answer: D

Rationale: To find 80% of $500, you multiply 0.8 by 500. Therefore, 0.8 x 500 = $400. This means that option D, $400, is the correct answer. Option A, $425, is incorrect because it is higher than the calculated value. Option B, $450, is also higher than the correct answer. Option C, $350, is lower than the calculated value. Hence, the correct answer is D, $400.

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