chun mei earns a 5 commission on each appliance she sells if she sells a washer for 749 and a dryer for 689 what will her commission be
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HESI A2

HESI A2 Math Practice Test

1. Chun Mei earns a 5% commission on each appliance she sells. If she sells a washer for $749 and a dryer for $689, what will her commission be?

Correct answer: B

Rationale: To calculate Chun Mei's commission, we first find the total sales amount by adding the prices of the washer and dryer: $749 + $689 = $1438. Next, we calculate her 5% commission on this total sales amount: 0.05 * $1438 = $71.90. Therefore, Chun Mei's commission for selling both appliances will be $71.90. Choice B, $71.90, is the correct answer. Choices A, C, and D are incorrect as they do not reflect the accurate calculation of Chun Mei's commission based on the given scenario.

2. At the book sale, Geoff paid 35 cents apiece for 5 paperbacks and $50 apiece for 3 hardcover books. He gave the clerk a $10 bill. How much change did he receive?

Correct answer: B

Rationale: Geoff paid a total of 5 paperbacks x $0.35/paperback + 3 hardcover books x $50/hardcover book = $1.75 + $150 = $8.75. Since he gave the clerk a $10 bill, he received $10 - $8.75 = $1.25 change. However, since the options are in increments of $0.25, the closest amount is $0.75, so Geoff received $0.75 change. Option A is incorrect because it's not the closest amount to the actual change. Option C is incorrect as it represents the total change Geoff received, not the closest increment. Option D is incorrect as it overestimates the change Geoff received.

3. You need to repaint a cylindrical water tank with a diameter of 2 meters and a height of 3 meters. Assuming one can of paint covers 10 sq m, how many cans do you need to cover only the exterior surface?

Correct answer: C

Rationale: To find the surface area of the cylinder, calculate the lateral surface area using the formula 2πrh, where r is the radius (half of the diameter) and h is the height. Substituting the values, we get 2 * π * 1 * 3 = 6π square meters. Since each can covers 10 sq m, divide the total surface area by the coverage area per can: 6π / 10 ≈ 1.9 cans. Since you can't buy a fraction of a can, you would need to round up, so you would need 2 cans to cover the entire exterior surface. Therefore, you would need 2 * 6 = 12 cans in total. Choices A, B, and D are incorrect as they do not consider the correct surface area calculation or the rounding up to the nearest whole number of cans required.

4. A farmer wants to plant trees at the outside boundaries of his rectangular field with dimensions 650 meters × 780 meters. Each tree requires 5 meters of free space all around it from the stem. How much free area will be left?

Correct answer: A

Rationale: To calculate the area taken by the trees, we need to account for the space each tree requires. Each tree needs 5 meters of free space all around it, totaling 10 meters added to each dimension. Therefore, the new dimensions of the field are (650-10) meters by (780-10) meters. Calculating the area of the new field: (640m × 770m = 492,800m²). To find the free area remaining, subtract the new field's area from the original field's area: 507,000m² - 492,800m² = 14,200m². Therefore, the free area left after planting the trees is 14,200m². Choice A is the correct answer as it represents the free area left after planting the trees.

5. If a rat can finish a maze in about 3 minutes, how much longer will it take the rat to finish the maze if a small backpack is put on it, reducing its speed by 50%?

Correct answer: C

Rationale: Reducing the rat's speed by 50% means it will take twice as long to finish the maze. Since the original time is 3 minutes, doubling that gives 6 minutes. Therefore, the total time will be 6 minutes, making the correct answer C. Choice A (3 minutes) is the original time it takes the rat to finish the maze, not the time with the backpack. Choice B (4 minutes) is not correct as reducing the speed by 50% would double the original time. Choice D (1.5 minutes) is incorrect as halving the time is not the effect of reducing the speed by 50%.

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