solve the following equation 4y 6 14 solve for y
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HESI A2

HESI A2 Quizlet Math

1. What is the solution to the equation 4y - 6 = 14? Solve for y.

Correct answer: B

Rationale: To solve the equation 4y - 6 = 14 for y, isolate y by adding 6 to both sides: 4y = 14 + 6 => 4y = 20. Then, divide by 4 to solve for y: y = 20 ÷ 4 = 5. Therefore, the correct answer is 5. Choice A is incorrect as it does not represent the correct solution to the equation. Choice C is incorrect as it is not the solution obtained after correctly solving the equation. Choice D is incorrect as it is not the correct solution to the given equation.

2. Calculate the product of (99)(0.56) =

Correct answer: C

Rationale: To find the product of 99 and 0.56, multiply the two numbers: 99 x 0.56 = 55.44. Therefore, the correct answer is 55.44.

3. How many pounds are in 128 ounces?

Correct answer: D

Rationale: The correct answer is D, 8 pounds. There are 16 ounces in a pound. To convert 128 ounces to pounds, you divide 128 by 16, which equals 8 pounds. Choice A, 16 pounds, is incorrect because that would be the conversion the other way around, from pounds to ounces. Choices B and C are incorrect as they do not reflect the correct conversion from ounces to pounds.

4. What is 70% of 65?

Correct answer: B

Rationale: To find 70% of 65, you multiply 0.7 by 65. Mathematically, 0.7 * 65 = 45.5. Therefore, the correct answer is 45.5. Choice A (40.5) is incorrect because it is not the result of multiplying 0.7 by 65. Choice C (50) is incorrect as it is higher than the correct answer. Choice D (55) is also higher than the correct result and is therefore incorrect.

5. Convert 2/5 to a decimal.

Correct answer: C

Rationale: To convert 2/5 to a decimal, you divide the numerator (2) by the denominator (5): 2 ÷ 5 = 0.4. Therefore, the correct decimal representation of 2/5 is 0.4. Choice A (0.5) is incorrect because it represents 1/2, not 2/5. Choice B (0.25) is incorrect as it represents 1/4, not 2/5. Choice D (0.5) is incorrect as it also represents 1/2, not 2/5.

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