what is the absolute value of 7

HESI A2

HESI A2 Math Practice Test

1. What is the absolute value of -7?

A. 49
B. 17
C. 7
D. 14

Correct answer: C

Rationale: The absolute value of a number is its distance from zero on the number line, regardless of its sign. In this case, the absolute value of -7 is 7 because it is 7 units away from zero in the negative direction. Therefore, the absolute value of -7 is 7. Choice A (49) is incorrect as it is the square of -7, not the absolute value. Choice B (17) and Choice D (14) are incorrect values and do not represent the absolute value of -7.

2. In a table showing blood pressure readings for different age groups, how do you determine the patient with the highest systolic pressure?

A. Find the largest number in the 'systolic pressure' column.
B. Compare the means (averages) of each age group.
C. Add all systolic pressure values and divide by the total number of patients.
D. Subtract the lowest systolic pressure from the highest.

Correct answer: A

Rationale: To determine the patient with the highest systolic pressure from the table, you should find the largest number in the 'systolic pressure' column. This method directly identifies the individual with the highest systolic pressure. Comparing the means (averages) of each age group, as suggested in choice B, may not pinpoint the specific patient with the highest systolic pressure, as averages can sometimes mask extreme values. Adding all systolic pressure values and dividing by the total number of patients, as in choice C, calculates the average systolic pressure for all patients, not identifying the highest individual reading. Subtracting the lowest systolic pressure from the highest, as in choice D, determines the range of systolic pressures but does not directly point out the patient with the highest reading.

3. How many centimeters are in 6 meters?

A. 600 cm
B. 60 cm
C. 1000 cm
D. 500 cm

Correct answer: A

Rationale: To convert meters to centimeters, you need to multiply the number of meters by 100 since there are 100 centimeters in 1 meter. Therefore, 6 meters is equal to 6 * 100 = 600 cm. Choice A is correct. Choice B (60 cm) is incorrect because it represents the conversion of 0.6 meters to centimeters. Choice C (1000 cm) is incorrect because it represents the conversion of 10 meters to centimeters. Choice D (500 cm) is incorrect because it is halfway between the conversions of 5 meters (500 cm) and 6 meters (600 cm).

4. A healthcare professional works in a military hospital from 1300 to 2000. What time of day does this healthcare professional work?

A. Early morning to early afternoon
B. Lunchtime to midnight
C. Early afternoon to bedtime
D. Midnight to sunrise

Correct answer: C

Rationale: The correct answer is C: Early afternoon to bedtime. The healthcare professional's work hours from 1300 to 2000 correspond to 1 PM to 8 PM, indicating work during the afternoon and early evening. Choice A (Early morning to early afternoon) is incorrect because the professional works in the afternoon and early evening, not the morning. Choice B (Lunchtime to midnight) is incorrect as the professional finishes work before midnight, not until midnight. Choice D (Midnight to sunrise) is incorrect as the professional's work hours are during the daytime and evening, not overnight.

5. Leslie is blowing up her favorite photograph. If the photo's original height was 15 inches and the new height is 4 feet, how many feet must the new width be?

A. 2.1 feet
B. 4 feet
C. 3 feet
D. 5 feet

Correct answer: A

Rationale: To find the new width, we need to maintain the aspect ratio of the photo. The original height is 15 inches, which is equivalent to 1.25 feet. If the new height is 4 feet, the scaling factor for the height is 4/1.25 = 3.2. Therefore, to find the new width, we multiply the original width by this scaling factor: 1.25 feet * 3.2 ≈ 4 feet. So, the correct answer is approximately 2.1 feet (4 feet * (15 inches / 4 feet) ≈ 2.1 feet). Choices B, C, and D are incorrect as they do not consider the aspect ratio and calculate the new width incorrectly.