Nursing Elites

1. Jeff needed a 6 ft. rope. He found 2 pieces of rope and thought maybe he could tie them together. One rope was 40 inches and the other was 36 inches. How long would the rope be, and would he have enough rope if he ties them together?

• A. No, the rope would be 76 inches.
• B. Yes, the rope would be 76 inches.
• C. Yes, the rope would be 6 feet.
• D. No, the rope would be 6 feet.

Correct answer: B

Rationale: To convert 6 feet to inches, we multiply 6 by 12 (1 foot = 12 inches), giving us 72 inches needed. By adding the lengths of the two ropes (40 inches + 36 inches), Jeff would have a total of 76 inches, which is more than the 72 inches required. Therefore, he would have enough rope if he ties them together. Choice A and D are incorrect because they misinterpret the conversion from feet to inches. Choice C is incorrect as it does not consider the actual combined length of the two ropes.

2. Karen goes to the grocery store with $40. She buys a carton of milk for $1.85, a loaf of bread for $3.20, and a bunch of bananas for $3.05. How much money does she have left?

• A. $30.95
• B. $31.90
• C. $32.10
• D. $34.95

Correct answer: B

Rationale: To determine how much money Karen has left, we first calculate the total cost of the items she bought: $1.85 + $3.20 + $3.05 = $8.10. Subtracting this total cost from the initial amount she had, $40 - $8.10 = $31.90 left. Choice A, $30.95, is incorrect as it does not reflect the correct amount left after subtracting the total cost. Choice C, $32.10, is incorrect as it is the total cost of the items she bought, not the amount left. Choice D, $34.95, is incorrect as it does not consider the expenses incurred and subtracted from the initial amount.

3. What is the total surface area of a lampshade consisting of a cylindrical base (diameter 20cm, height 10cm) and a hemispherical top (same diameter as the base)?

• A. 785 sq cm
• B. 1130 sq cm
• C. 1570 sq cm
• D. 2055 sq cm

Correct answer: D

Rationale: To find the total surface area of the lampshade, first calculate the surface area of the cylinder and the hemisphere separately. 1. Surface area of the cylinder = 2πr² + 2πrh = 2π(10)² + 2π(10)(20) = 400π + 400π = 800π cm². 2. Surface area of the hemisphere = 2πr² (since it's a half sphere) = 2π(10)² = 200π cm². Adding both areas gives the total surface area: 800π + 200π = 1000π cm². Now, calculate the numerical value: 1000π ≈ 3141.59 cm², which is approximately equal to 2055 cm². Therefore, the correct answer is 2055 sq cm. Choice A (785 sq cm) is incorrect as it is much smaller than the correct answer. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not account for the total surface area of the lampshade.

4. What is the volume of a birthday party hat with a cone-shaped top having a radius of 5cm and a height of 12cm?

• A. 60 cu cm
• B. 120 cu cm
• C. 150 cu cm
• D. 180 cu cm

Correct answer: C

Rationale: To find the volume of a cone, we use the formula: (1/3) * π * (radius)^2 * height. Substituting the given values: (1/3) * π * (5cm)^2 * 12cm = 150 cu cm. Therefore, the correct answer is C. Choice A, B, and D are incorrect as they do not correspond to the correct calculation using the formula for the volume of a cone.

5. What is the probability of rolling a 5 on a six-sided die?

• A. 1/6
• B. 1/4
• C. 1/2
• D. 1/3

Correct answer: A

Rationale: The probability of rolling a specific number on a fair six-sided die is calculated by dividing the number of favorable outcomes (1 in this case, as there is one '5' on the die) by the total number of possible outcomes (6 for a six-sided die), resulting in a probability of 1/6. Therefore, the correct answer is A. Choices B, C, and D are incorrect because they do not accurately represent the probability of rolling a 5 on a six-sided die. Option B (1/4) is incorrect because it represents the probability of rolling a specific number on a four-sided die. Option C (1/2) and Option D (1/3) are incorrect as they do not match the probability calculation for rolling a 5 on a six-sided die.

Similar Questions