Nursing Elites

1. Your supervisor instructs you to purchase 240 pens and 6 staplers for the nurse's station. Pens are purchased in sets of 6 for $2.35 per pack. Staplers are sold in sets of 2 for $12.95 each. How much will purchasing these products cost?

• A. $162.00
• B. $132.00
• C. $225.00
• D. $145.00

Correct answer: B

Rationale: To find the total cost, first calculate the cost of pens and staplers separately. 240 pens require 40 packs (240 pens ÷ 6 pens per pack = 40 packs). Each pack of pens costs $2.35, so 40 packs cost $94 (40 packs × $2.35 per pack = $94). For the staplers, 6 staplers require 3 packs (6 staplers ÷ 2 staplers per pack = 3 packs). Each pack of staplers costs $12.95, so 3 packs cost $38.85 (3 packs × $12.95 per pack = $38.85). Adding the cost of pens and staplers together gives a total of $132.85, which rounds to $132.00. Therefore, the correct answer is $132.00. Choice A is incorrect as it does not consider the individual prices of pens and staplers. Choice C is incorrect as it overestimates the total cost by combining the costs incorrectly. Choice D is incorrect as it underestimates the total cost by not considering both pens and staplers.

2. After taking several practice tests, Brian improved the results of his GRE test by 30%. Given that the first time he took the test Brian answered 150 questions correctly, how many questions did he answer correctly on the second test?

• A. 105
• B. 120
• C. 180
• D. 195

Correct answer: D

Rationale: If Brian answered 150 questions correctly on the first test, after improving his results by 30%, he would have answered (150 * 1.30) = 195 questions correctly on the second test. Therefore, the correct answer is 195, option D. Choices A, B, and C are incorrect as they do not account for the 30% improvement in the number of questions Brian answered correctly on the second test.

3. The physician ordered 3,000 units of heparin; 5,000 U/mL is on hand. How many milliliters will you give?

• A. 0.5 ml
• B. 0.6 ml
• C. 0.75 ml
• D. 0.8 ml

Correct answer: B

Rationale: To calculate the volume of heparin needed, use the formula: Volume of Heparin = (Ordered Units / Concentration of Heparin). Substituting the values, Volume = (3,000 units / 5,000 U/mL) = 0.6 ml. Therefore, the correct answer is 0.6 ml. Choice A (0.5 ml) is incorrect as it results from an incorrect calculation. Choices C (0.75 ml) and D (0.8 ml) are also incorrect calculations based on the wrong formula application or mathematical errors.

4. A runner leaves at 7:45 for a morning run at an average speed of 6 mph and returns at 10:00. How many miles did he run?

• A. 11.5 miles
• B. 14.5 miles
• C. 12 miles
• D. 13.5 miles

Correct answer: D

Rationale: The runner left at 7:45 and returned at 10:00, which means he ran for 2 hours and 15 minutes (10:00 - 7:45). At an average speed of 6 mph, in 2.25 hours, he would have covered 6 mph * 2.25 hours = 13.5 miles. Therefore, the correct answer is 13.5 miles. Choices A, B, and C are incorrect because they incorrectly calculate the distance based on the time and speed provided in the question.

5. A decorative box has a rectangular base (20cm by 15cm) and a hemispherical top with the same diameter as the base. What is the total surface area of the box (excluding the base)?

• A. 825 sq cm
• B. 1075 sq cm
• C. 1325 sq cm
• D. 1575 sq cm

Correct answer: C

Rationale: To find the total surface area of the box excluding the base, calculate the lateral surface area of the rectangular base and the surface area of the hemisphere. The lateral surface area of the rectangular base is 2(20cm x 15cm) = 600 sq cm. The surface area of the hemisphere is 2πr^2, where r is half the diameter of the base, so r = 10cm. Thus, the surface area of the hemisphere is 2π(10cm)^2 = 200π sq cm ≈ 628.32 sq cm. Add the lateral surface area of the base and the surface area of the hemisphere: 600 sq cm + 628.32 sq cm ≈ 1228.32 sq cm. Therefore, the total surface area of the box is approximately 1228.32 sq cm, which is closest to 1325 sq cm (Choice C). Choices A, B, and D are incorrect as they do not represent the accurate calculation of the total surface area of the box.

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