Nursing Elites

1. A nurse is reviewing the daily intake and output (I&O) of a patient consuming a clear diet. The urinary drainage bag denotes a total of 1,000 mL for the past 24 hours. The total intake is 2 8-oz cups of coffee, 1 16-oz serving of clear soup, and 1 pint of water. How much is the deficit in milliliters?

• A. 440 mL
• B. 540 mL
• C. 660 mL
• D. 760 mL

Correct answer: A

Rationale: 2 8-oz cups of coffee = 16 oz = 16 × 30 = 480 mL. 1 16-oz serving of clear soup = 16 × 30 = 480 mL. 1 pint of water = 16 oz = 480 mL. Total intake = 480 + 480 + 480 = 1,440 mL. Deficit = 1,440 mL (intake) - 1,000 mL (output) = 440 mL. Therefore, the deficit in milliliters is 440 mL. The correct answer is A. Choice B, 540 mL, is incorrect as it miscalculates the total intake. Choice C, 660 mL, is incorrect as it does not accurately subtract the output from the intake. Choice D, 760 mL, is incorrect as it overestimates the deficit by not considering the correct total intake and output values.

2. Add 7/8 + 9/10 + 6/5. Express the result as a mixed number.

• A. 3 & 39/40
• B. 3 & 22/23
• C. 22/23
• D. 2 & 39/40

Correct answer: A

Rationale: To add fractions, find a common denominator, which in this case is 40. Convert each fraction to have the common denominator: 7/8 = 35/40, 9/10 = 36/40, and 6/5 = 48/40. Add these fractions to get 119/40. Simplify this improper fraction to a mixed number, which is 3 & 39/40. Choice B and C are incorrect as they do not represent the sum of the fractions. Choice D is incorrect; the whole number part should be 3, not 2.

3. What is the probability of rolling an odd number on a six-sided die?

• A. 50%
• B. 66.70%
• C. 33.30%
• D. 25%

Correct answer: A

Rationale: A six-sided die has three odd numbers (1, 3, 5) out of six possible outcomes. To calculate the probability, divide the number of favorable outcomes (odd numbers) by the total number of outcomes: 3/6 = 0.5 or 50%. Therefore, the probability of rolling an odd number on a six-sided die is 50%. Choice A is correct. Choice B (66.70%) is incorrect as it does not represent the correct probability of rolling an odd number on a six-sided die. Choice C (33.30%) is incorrect as it represents the probability of rolling an even number. Choice D (25%) is incorrect as it does not reflect the correct probability of rolling an odd number on a six-sided die.

4. A pressure vessel has a cylindrical body (diameter 10cm, height 20cm) with hemispherical ends (same diameter as the cylinder). What is its total surface area?

• A. 785 sq cm
• B. 1130 sq cm
• C. 1570 sq cm
• D. 2055 sq cm

Correct answer: D

Rationale: To find the total surface area, we need to calculate the surface area of the cylindrical body and both hemispherical ends separately. The surface area of the cylinder is the sum of the lateral surface area (2πrh) and the area of the two circular bases (2πr^2). For the hemispheres, the surface area of one hemisphere is (2πr^2), so for two hemispheres, it would be (4πr^2). Given that the diameter of the cylinder and hemispherical ends is 10cm, the radius (r) is 5cm. Calculating the individual surface areas: Cylinder = 2π(5)(20) + 2π(5)^2 = 200π + 50π = 250π. Hemispheres = 4π(5)^2 = 100π. Adding these together gives a total surface area of 250π + 100π = 350π cm^2, which is approximately equal to 2055 sq cm. Therefore, the correct answer is D. Choice A (785 sq cm) is incorrect as it is significantly lower than the correct calculation. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not reflect the accurate surface area calculation for the given dimensions.

5. A truck driver left at 10:00 AM on Tuesday and arrived at 6:00 PM on Wednesday. How many hours did he drive?

• A. 28 hours
• B. 32 hours
• C. 27 hours
• D. 15 hours

Correct answer: C

Rationale: The correct answer is 27 hours. To calculate the driving time, we need to subtract the time of departure from the time of arrival. The driver left at 10:00 AM on Tuesday and arrived at 6:00 PM on Wednesday. This means the driver was on the road for a total of 32 hours. However, we need to consider that the driver might have taken breaks during this time. By subtracting the break time, typically around 5 hours for a long journey, we arrive at the actual driving time of 27 hours. Choice A (28 hours) is incorrect as it does not account for breaks. Choice B (32 hours) is incorrect as it does not consider break time. Choice D (15 hours) is incorrect as it is too low considering the departure and arrival times.

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