Nursing Elites

1. A client is receiving an epidural block with an opioid analgesic. The nurse should monitor for which of the following findings as an adverse effect of the medication?

• A. Hypotension
• B. Polyuria
• C. Bilateral crackles
• D. Hyperglycemia

Correct answer: C

Rationale: The correct answer is C: Bilateral crackles. Bilateral crackles indicate respiratory complications, which can occur as an adverse effect of an epidural block with opioid analgesics. Hypotension (Choice A) is a common side effect of epidural opioids but is not typically monitored via crackles. Polyuria (Choice B) is excessive urination and is not directly associated with epidural blocks. Hyperglycemia (Choice D) is high blood sugar levels and is not a typical adverse effect of epidural opioids.

2. A nurse is teaching about clomiphene citrate to a client who is experiencing infertility. Which of the following adverse effects should the nurse include?

• A. Tinnitus
• B. Urinary Frequency
• C. Breast Tenderness
• D. Chills

Correct answer: C

Rationale: The correct answer is C: 'Breast Tenderness.' Clomiphene citrate is known to cause breast tenderness as a common side effect due to its hormonal effects on the body. Tinnitus (choice A), which is a ringing in the ears, is not typically associated with clomiphene citrate. Urinary frequency (choice B) is not a common adverse effect of this medication. Chills (choice D) are also not commonly linked to clomiphene citrate use.

3. Before meiosis, a sperm cell:

• A. contains 46 chromosomes.
• B. contains two X chromosomes.
• C. is significantly larger than an egg cell.
• D. contains both an X and a Y chromosome.

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

4. A client who has mild preeclampsia and will be caring for herself at home during the last 2 months of pregnancy is receiving teaching from a healthcare provider. Which statement by the client indicates an understanding of the teaching?

• A. “I will count baby’s kicks every other day.”
• B. “I will alternate the arm used to check my blood pressure.”
• C. “I will consume 50 grams of protein daily.”
• D. ---

Correct answer: B

Rationale: The correct answer is B. Alternating arms for blood pressure checks ensures more accurate readings and helps monitor preeclampsia. Option A, counting baby's kicks every other day, is not specific to managing preeclampsia. Option C, consuming 50 grams of protein daily, is important for a healthy diet during pregnancy but does not directly relate to preeclampsia management.

5. Humans begin life as a single cell that divides repeatedly. This cell is known as a(n):

• A. zygote.
• B. gonadotrope.
• C. embryo.
• D. chromaffin.

Correct answer: A

Rationale: A zygote is the correct answer. It is the initial cell formed when a sperm cell fertilizes an egg cell, marking the beginning of human development. Choice B, gonadotrope, is incorrect as it refers to a type of hormone-secreting cell in the pituitary gland. Choice C, embryo, is incorrect as it is the stage of development after the zygote has implanted into the uterine wall and undergone initial cell divisions. Choice D, chromaffin, is incorrect as it refers to cells found in the adrenal medulla that produce and store catecholamines.

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