Nursing Elites

1. Twins that derive from a single zygote that has split into two are called:

• A. monozygotic (MZ) twins.
• B. fraternal twins.
• C. non-identical twins.
• D. dizygotic (DZ) twins.

Correct answer: A

Rationale: The correct answer is A: monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, occur when a single zygote splits into two embryos, leading to two genetically identical individuals. Choice B, fraternal twins, are twins that develop from two separate eggs fertilized by two different sperm cells, resulting in non-identical siblings. Choice C, non-identical twins, is not a common term used to describe this type of twinning. Choice D, dizygotic (DZ) twins, refer to twins that develop from two separate eggs fertilized by two different sperm cells, leading to non-identical twins.

2. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

3. Is a low sperm count or lack of sperm the most common infertility problem in men?

• A. TRUE
• B. FALSE
• C. Rarely
• D. Never

Correct answer: A

Rationale: A low sperm count or lack of sperm is indeed one of the most common causes of infertility in men. Factors such as hormonal imbalances, genetic issues, reproductive anatomy problems, and lifestyle factors can also contribute to male infertility. Choice B is incorrect because a low sperm count is a prevalent issue among men facing infertility, making it a common problem. Choices C and D are incorrect as they do not accurately reflect the prevalence of low sperm count as a cause of infertility in men.

4. Four clients at full term present to the labor and delivery unit at the same time. Which client should a nurse assess first?

• A. Multipara with contractions occurring every three minutes
• B. Multipara scheduled for non-stress test and biophysical profile
• C. Primipara with vaginal show and leaking membranes
• D. Primipara with burning on urination and urinary frequency

Correct answer: C

Rationale: A primipara with vaginal show and leaking membranes requires immediate assessment as she may be in active labor or at risk of infection. The vaginal show and leaking membranes suggest potential rupture of membranes and the start of labor. Assessing her first ensures prompt management and monitoring. The other options, while important, do not indicate immediate or emergent needs. Contractions every three minutes in a multipara can be managed with ongoing monitoring; non-stress tests and biophysical profiles can be scheduled and are not acute needs. Burning on urination and urinary frequency in a primipara may indicate a urinary tract infection, which is important but not as urgent as assessing for active labor or rupture of membranes.

5. After a mother was diagnosed with gonorrhea immediately after delivery, what is an important goal of the nurse when providing care for her baby?

• A. Prevent the development of ophthalmia neonatorum.
• B. Lubricate the eyes.
• C. Prevent the development of infection.
• D. Teach about the risks of breastfeeding with gonorrhea.

Correct answer: A

Rationale: The correct answer is A: Prevent the development of ophthalmia neonatorum. When a mother has gonorrhea, the baby can be infected during delivery, leading to ophthalmia neonatorum, which can cause permanent blindness. Therefore, it is crucial for the nurse to prevent this condition by treating the baby's eyes with an antibiotic prophylactically after birth. Choice B, lubricating the eyes, is not the primary goal in this situation as preventing infection takes precedence. Choice C, preventing the development of infection, is too broad and does not specifically address the potential complication of ophthalmia neonatorum. Choice D, teaching about the risks of breastfeeding with gonorrhea, is important but not the immediate goal in this scenario where preventing ophthalmia neonatorum and potential blindness is the priority.

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