Nursing Elites

1. A cell containing 12 chromosomes divides into daughter cells in mitosis. How many chromosomes are in each daughter cell?

• A. 3
• B. 6
• C. 12
• D. 24

Correct answer: C

Rationale: During mitosis, the cell undergoes nuclear division without changing the number of chromosomes. Therefore, the daughter cells produced will have the same number of chromosomes as the parent cell. In this case, since the parent cell contains 12 chromosomes, each daughter cell will also have 12 chromosomes. Choices A, B, and D are incorrect because during mitosis, the chromosome number remains the same, and daughter cells inherit the same number of chromosomes as the parent cell.

2. Athletes are often concerned with the question of what they need in their diets to increase muscle mass and strength. What biologic molecule would you recommend that would accomplish this?

• A. carbohydrates
• B. proteins
• C. lipids
• D. nucleic acids

Correct answer: B

Rationale: Proteins are essential for building and repairing muscle tissue. They contain amino acids, which are the building blocks of muscles. Athletes looking to increase muscle mass and strength should focus on consuming adequate amounts of high-quality proteins in their diets. Carbohydrates provide energy for workouts, lipids are important for overall health but do not directly contribute to muscle building, and nucleic acids are involved in genetic activities rather than muscle growth.

3. In a phospholipid molecule, the head:

• A. Is hydrophilic
• B. Is hydrophobic
• C. Is on the inner side of the layer
• D. Both A and C

Correct answer: D

Rationale: The head of a phospholipid is hydrophilic (water-loving) and is located on the outer side of the lipid bilayer, interacting with water molecules. This arrangement positions the hydrophobic tails inward, away from water. Therefore, the correct answer is D. Choice A is incorrect because the head is hydrophilic, not hydrophobic. Choice B is incorrect as the head is on the outer side, not the inner side of the layer.

4. Huntington’s disease is carried on the dominant allele. In a situation where two heterozygous parents have the disease, what percentage of their offspring are predicted to be disease-free?

• A. 0%
• B. 25%
• C. 50%
• D. 100%

Correct answer: B

Rationale: In this scenario, both parents are heterozygous for Huntington's disease, meaning each carries one dominant allele (representing the disease) and one recessive allele (representing no disease). When they have offspring, there is a 25% chance that each child will inherit two recessive alleles, making them disease-free. The Punnett square for two heterozygous parents (Hh x Hh) yields a 25% probability of offspring being homozygous recessive (hh) and therefore disease-free. Choice A (0%) is incorrect because there is a possibility of disease-free offspring. Choice C (50%) is incorrect as it represents the likelihood of being a carrier. Choice D (100%) is incorrect as all offspring will not be disease-free in this scenario.

5. How does yeast reproduce?

• A. Binary fission
• B. Spore formation
• C. Budding
• D. Cloning

Correct answer: C

Rationale: Yeast typically reproduces through a process called budding. During budding, a small outgrowth forms on the parent yeast cell, gradually enlarging in size until it separates to become a new, genetically identical daughter cell. This method of reproduction allows yeast to rapidly multiply and grow in favorable conditions. It is different from binary fission, spore formation, and cloning. Binary fission involves the division of a single organism into two genetically identical organisms. Spore formation is a method seen in certain fungi where specialized cells develop into spores for reproduction. Cloning involves producing genetically identical copies of an organism. Therefore, budding is the correct answer for how yeast reproduces.

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