Nursing Elites

1. What nursing diagnosis is the most appropriate for a woman experiencing severe preeclampsia?

• A. Risk for injury to mother and fetus, related to central nervous system (CNS) irritability.
• B. Risk for altered gas exchange.
• C. Risk for deficient fluid volume, related to increased sodium retention secondary to the administration of magnesium sulfate.
• D. Risk for increased cardiac output, related to the use of antihypertensive drugs.

Correct answer: A

Rationale: The most appropriate nursing diagnosis for a woman experiencing severe preeclampsia is 'Risk for injury to mother and fetus, related to central nervous system (CNS) irritability.' Severe preeclampsia poses a significant risk of injury to both the mother and the fetus due to complications such as seizures, stroke, and placental abruption. 'Risk for altered gas exchange' is not the priority diagnosis as pulmonary edema is more common in severe preeclampsia. 'Risk for deficient fluid volume' is incorrect as sodium retention in severe preeclampsia often leads to fluid overload. 'Risk for increased cardiac output' is also incorrect as antihypertensive drugs are used to reduce cardiac output in this condition.

2. Monozygotic (MZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

3. According to a survey by Adhikari and Liu in the year 2013, at birth, women have:

• A. close to 100,000 ova.
• B. around 300,000 to 400,000 ova.
• C. around 100 to 200 ova.
• D. only 500 ova.

Correct answer: B

Rationale: Women are born with approximately 300,000 to 400,000 ova, which gradually decrease in number as they age. Choice A ('close to 100,000 ova.') is incorrect as the actual number is much higher. Choice C ('around 100 to 200 ova.') is incorrect as it underestimates the quantity significantly. Choice D ('only 500 ova.') is incorrect as it greatly underestimates the number of ova present at birth.

4. Which of the following is most likely to develop sickle cell anemia?

• A. European American
• B. Native American
• C. African American
• D. Asian American

Correct answer: C

Rationale: Sickle cell anemia is most commonly found in individuals of African American descent. This is because sickle cell trait provides some protection against malaria, and historically, regions where malaria is or was prevalent have higher rates of sickle cell anemia. Therefore, individuals with African ancestry are at a higher risk of developing sickle cell anemia compared to other populations. Choices A, B, and D are less likely to develop sickle cell anemia due to lower genetic prevalence in their respective populations.

5. Humans begin life as a single cell that divides repeatedly. This cell is known as a(n):

• A. zygote.
• B. gonadotrope.
• C. embryo.
• D. chromaffin.

Correct answer: A

Rationale: A zygote is the correct answer. It is the initial cell formed when a sperm cell fertilizes an egg cell, marking the beginning of human development. Choice B, gonadotrope, is incorrect as it refers to a type of hormone-secreting cell in the pituitary gland. Choice C, embryo, is incorrect as it is the stage of development after the zygote has implanted into the uterine wall and undergone initial cell divisions. Choice D, chromaffin, is incorrect as it refers to cells found in the adrenal medulla that produce and store catecholamines.

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