Nursing Elites

1. The nurse places one hand above the symphysis while massaging the fundus of a multiparous client whose uterine tone is boggy 15 minutes after delivering a 7-pound, 10-ounce (3220-gram) infant. Which information should the nurse provide to the client about these findings?

• A. The uterus should be firm to prevent an intrauterine infection.
• B. Both the lower uterine segment and the fundus must be massaged.
• C. A firm uterus prevents the endometrial lining from being sloughed.
• D. Clots may form inside a boggy uterus and need to be expelled.

Correct answer: D

Rationale: After childbirth, a boggy uterus indicates poor uterine tone, which can lead to the formation of clots. Massaging the fundus helps the uterus contract and expel clots, reducing the risk of postpartum hemorrhage. Choices A, B, and C are incorrect because the main concern with a boggy uterus is the risk of clot formation and postpartum hemorrhage, not solely preventing intrauterine infection, massaging the lower uterine segment, or preventing the endometrial lining from sloughing.

2. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

3. A client is preparing to administer methylergonovine 0.2 mg orally to a client who is 2 hr postpartum and has a boggy uterus. For which of the following assessment findings should the nurse withhold the medication?

• A. Blood pressure 142/92 mm Hg
• B. Urine output 100 mL in 1 hr
• C. Pulse 58/min
• D. Respiratory rate 14/min

Correct answer: A

Rationale: The correct answer is A. Methylergonovine can increase blood pressure, so it should be withheld if the client has hypertension. A blood pressure reading of 142/92 mm Hg indicates hypertension and is a contraindication for administering methylergonovine. Choices B, C, and D are within normal limits and not contraindications for administering this medication. Urine output, pulse rate, and respiratory rate are not factors that determine the appropriateness of administering methylergonovine in this situation.

4. Which of the following is most likely to develop sickle cell anemia?

• A. European American
• B. Native American
• C. African American
• D. Asian American

Correct answer: C

Rationale: Sickle cell anemia is most commonly found in individuals of African American descent. This is because sickle cell trait provides some protection against malaria, and historically, regions where malaria is or was prevalent have higher rates of sickle cell anemia. Therefore, individuals with African ancestry are at a higher risk of developing sickle cell anemia compared to other populations. Choices A, B, and D are less likely to develop sickle cell anemia due to lower genetic prevalence in their respective populations.

5. Which of the following statements is true of a sperm cell?

• A. A sperm cell is significantly larger than an egg cell.
• B. A sperm cell contains two Y chromosomes.
• C. A sperm cell travels randomly inside a woman’s reproductive tract.
• D. A sperm cell is one of the smallest types of cells in the body.

Correct answer: D

Rationale: The correct answer is D. A sperm cell is indeed one of the smallest cells in the human body, much smaller than an egg cell. Choice A is incorrect as sperm cells are much smaller than egg cells. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not two Y chromosomes. Choice C is incorrect since sperm cells move in a purposeful manner guided by various factors within a woman's reproductive tract, not randomly.

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