HESI LPN
HESI Focus on Maternity Exam
1. Do sebaceous glands cause a developing organism to grow arms or wings, skin, or scales?
- A. True
- B. False
- C. Possibly
- D. Never
Correct answer: B
Rationale: The correct answer is B: False. Sebaceous glands are associated with the skin's oil production and have no role in the development of limbs or body coverings. Sebaceous glands primarily produce sebum, an oily substance that lubricates and waterproofs the skin and hair. Choices A, C, and D are incorrect because sebaceous glands do not influence the growth of arms, wings, skin, or scales in a developing organism.
2. After mitosis, the genetic code is identical in new cells unless _________ occur through radiation or other environmental influences.
- A. reductions
- B. expulsions
- C. conceptions
- D. mutations
Correct answer: D
Rationale: After mitosis, the genetic code is typically preserved and remains identical in the new cells. However, mutations can occur due to radiation or environmental influences, leading to changes in the DNA sequence and potentially altering the genetic code. Therefore, the correct answer is 'mutations.' Choices A, B, and C are incorrect because reductions, expulsions, and conceptions do not accurately describe the changes in the genetic code that can result from external factors. Mutations are the only option that reflects the alteration in the genetic code caused by external influences, making it the correct choice in this context.
3. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?
- A. Meconium-stained amniotic fluid
- B. Placenta previa
- C. Midline episiotomy
- D. Gestational hypertension
Correct answer: C
Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.
4. When assessing a woman in the first stage of labor, which clinical finding will alert the nurse that uterine contractions are effective?
- A. Dilation of the cervix.
- B. Descent of the fetus to –2 station.
- C. Rupture of the amniotic membranes.
- D. Increase in bloody show.
Correct answer: A
Rationale: During the first stage of labor, effective uterine contractions lead to cervical dilation. Dilation of the cervix is a key indicator that uterine contractions are progressing labor. Descent of the fetus to -2 station (Choice B) is related to the fetal position in the pelvis and not a direct indicator of uterine contraction effectiveness. Rupture of the amniotic membranes (Choice C) signifies the rupture of the fluid-filled sac surrounding the fetus and does not directly reflect uterine contraction effectiveness. An increase in bloody show (Choice D) can be a sign of impending labor, but it is not a direct indicator of uterine contraction effectiveness.
5. According to a study in the year 2013 by Fellman, if a woman is a twin, if her mother was a twin, or if she has previously borne twins, then:
- A. she will bear only monozygotic (MZ) twins.
- B. the chances of her becoming pregnant decrease.
- C. she is likely to be a healthy mother.
- D. the chances rise that she will bear twins.
Correct answer: D
Rationale: According to the study, the chances of a woman bearing twins increase if she is a twin herself, if her mother was a twin, or if she has previously borne twins. Therefore, the correct answer is D. Choice A is incorrect because the study does not specify that she will bear only monozygotic twins. Choice B is incorrect as the study does not mention any decrease in the chances of becoming pregnant. Choice C is incorrect because the study does not provide information about the woman's health status, focusing instead on the likelihood of bearing twins.
Similar Questions
Access More Features
HESI LPN Basic
$69.99/ 30 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access
HESI LPN Premium
$149.99/ 90 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access