Nursing Elites

1. Humans begin life as a single cell that divides repeatedly. This cell is known as a(n):

• A. zygote.
• B. gonadotrope.
• C. embryo.
• D. chromaffin.

Correct answer: A

Rationale: A zygote is the correct answer. It is the initial cell formed when a sperm cell fertilizes an egg cell, marking the beginning of human development. Choice B, gonadotrope, is incorrect as it refers to a type of hormone-secreting cell in the pituitary gland. Choice C, embryo, is incorrect as it is the stage of development after the zygote has implanted into the uterine wall and undergone initial cell divisions. Choice D, chromaffin, is incorrect as it refers to cells found in the adrenal medulla that produce and store catecholamines.

2. A 25-year-old gravida 3, para 2 client gave birth to a 9-pound, 7-ounce boy 4 hours ago after augmentation of labor with oxytocin (Pitocin). She presses her call light and asks for her nurse right away, stating 'I’m bleeding a lot.' What is the most likely cause of postpartum hemorrhage in this client?

• A. Retained placental fragments.
• B. Unrepaired vaginal lacerations.
• C. Uterine atony.
• D. Puerperal infection.

Correct answer: C

Rationale: Uterine atony is the most likely cause of bleeding 4 hours after delivery, especially after delivering a macrosomic infant and augmenting labor with oxytocin. Uterine atony is characterized by the inability of the uterine muscles to contract effectively after childbirth, leading to excessive bleeding. The other options, such as retained placental fragments (A), unrepaired vaginal lacerations (B), and puerperal infection (D), are less likely causes of postpartum hemorrhage in this scenario. Retained placental fragments can cause bleeding, but this typically presents earlier than 4 hours postpartum. Unrepaired vaginal lacerations would likely be evident sooner and not typically result in significant bleeding. Puerperal infection is not a common cause of immediate postpartum hemorrhage unless there are other signs of infection present.

3. A client has experienced a fetal demise following a vaginal delivery at term. What should the nurse advise the client?

• A. “You can bathe and dress your baby if you’d like to.”
• B. “If you don’t hold the baby, it will make letting go much harder.”
• C. “You should name the baby so he/she can have an identity.”
• D. “I’m sure you will be able to have another baby when you’re ready.”

Correct answer: A

Rationale: After a fetal demise, allowing the parents to bathe and dress their baby can offer them a sense of closure and help them in their grieving process. This act can provide a tangible way for the parents to bond with their baby and create lasting memories. Option B is incorrect because each individual may have different emotional needs and holding the baby may not be appropriate or helpful for everyone. Option C, while well-intentioned, may not be suitable for all parents as naming the baby could be emotionally challenging. Option D is insensitive as it overlooks the grieving process of losing a baby by suggesting a replacement.

4. What is the process in which the double helix of deoxyribonucleic acid (DNA) duplicates?

• A. Amniocentesis
• B. Mitosis
• C. Meiosis
• D. Mutation

Correct answer: B

Rationale: Mitosis is the correct answer because it is the process of cell division in which a cell duplicates its DNA and divides into two identical daughter cells. During mitosis, the DNA is replicated, and each daughter cell receives an identical copy of the genetic material. Amniocentesis is a medical procedure to collect amniotic fluid for prenatal genetic testing and is not related to DNA duplication. Meiosis is a type of cell division that produces gametes with half the genetic material of the parent cell, leading to genetic diversity. Mutation is a permanent alteration in the DNA sequence that can lead to genetic variations but is not the process of DNA duplication.

5. A client has bacterial vaginosis. Which of the following medications should the nurse expect to administer?

• A. Metronidazole
• B. Fluconazole
• C. Acyclovir
• D. Clindamycin

Correct answer: A

Rationale: Metronidazole is the correct choice for treating bacterial vaginosis as it is the first-line medication recommended for this condition. Metronidazole works by disrupting the DNA structure of bacteria, making it an effective treatment. Choice B, Fluconazole, is an antifungal medication primarily used for treating fungal infections, not bacterial vaginosis. Choice C, Acyclovir, is an antiviral medication used to treat viral infections, not bacterial vaginosis. Choice D, Clindamycin, is also used to treat bacterial infections but is not the first-line treatment for bacterial vaginosis, making it an incorrect choice in this scenario.

Similar Questions