Nursing Elites

1. A client who delivered a healthy newborn an hour ago asked the nurse when she can go home. Which information is most important for the nurse to provide the client?

• A. After the baby no longer demonstrates acrocyanosis
• B. After the baby receives the vitamin K injection
• C. When ambulating to avoid causing dizziness
• D. When there is no significant vaginal bleeding

Correct answer: D

Rationale: The most critical information for the nurse to provide the client is ensuring that there is no significant vaginal bleeding before discharge. This is vital to prevent complications such as postpartum hemorrhage. Options A, B, and C are important aspects of postpartum care, but assessing and managing vaginal bleeding takes precedence due to its potential seriousness.

2. Which of the following is a sexually transmitted infection that, in advanced stages, can attack major organ systems?

• A. Rubella
• B. Syphilis
• C. Cystic fibrosis
• D. Phenylketonuria

Correct answer: B

Rationale: Syphilis is the correct answer. Syphilis is a sexually transmitted infection caused by the bacterium Treponema pallidum. If left untreated, it can progress through various stages and potentially attack major organ systems, causing severe complications. Rubella, Cystic fibrosis, and Phenylketonuria are not sexually transmitted infections. Rubella is a viral infection, Cystic fibrosis is a genetic disorder affecting the lungs and digestive system, and Phenylketonuria is a genetic metabolic disorder. These conditions do not typically affect major organ systems in the same way as untreated syphilis.

3. Which of the following statements is true of Down’s syndrome?

• A. Down’s syndrome is usually caused by an extra copy of chromosome 21 in an individual.
• B. The symptoms of Down’s syndrome are similar to those of sickle-cell anemia.
• C. Down’s syndrome is caused by a sexually transmitted infection (STI) during conception.
• D. The probability of having a child with Down’s syndrome increases with the age of the parents.

Correct answer: D

Rationale: The correct answer is D. The likelihood of having a child with Down’s syndrome increases as the age of the parents increases, particularly the mother's age. Choice A is incorrect because Down’s syndrome is caused by an extra copy of chromosome 21, not a defect in the sex chromosomes. Choice B is incorrect as the symptoms of Down’s syndrome and sickle-cell anemia are different. Choice C is also incorrect as Down’s syndrome is not caused by a sexually transmitted infection during conception.

4. A nurse on the labor and delivery unit is assessing four clients. Which of the following clients is a candidate for an induction of labor with misoprostol?

• A. A client who has active genital herpes
• B. A client who has gestational diabetes mellitus
• C. A client who has a previous uterine incision
• D. A client who has placenta previa

Correct answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.

5. What is the typical sex chromosome pattern for females?

• A. XX
• B. XYY
• C. XY
• D. XXY

Correct answer: A

Rationale: The typical sex chromosome pattern for females is XX. Females have two X chromosomes, which is represented as XX. Choice B (XYY) is incorrect as it represents the sex chromosome pattern for males with an extra Y chromosome. Choice C (XY) is the sex chromosome pattern for males. Choice D (XXY) represents a genetic disorder known as Klinefelter syndrome, where males have an extra X chromosome.

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