an ancient egyptian pyramid has a square base with side lengths of 20 meters and a remaining height after erosion of 10 meters its original height was
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HESI A2

HESI A2 Math Portion

1. An ancient Egyptian pyramid has a square base with side lengths of 20 meters and a remaining height (after erosion) of 10 meters. Its original height was 30 meters. What was the volume of the pyramid in its original state?

Correct answer: A

Rationale: To find the volume of a pyramid, you can use the formula: Volume = (1/3) * base area * height. In this case, the base area is the square of side length 20 meters, which is 20 * 20 = 400 square meters. The original height of the pyramid is 30 meters. Therefore, the volume of the pyramid in its original state is (1/3) * 400 * 30 = 12000 cubic meters. Choice A is correct. Choices B, C, and D are incorrect as they do not correctly calculate the volume using the original height and base area of the pyramid.

2. Your supervisor instructs you to purchase 240 pens and 6 staplers for the nurse's station. Pens are purchased in sets of 6 for $2.35 per pack. Staplers are sold in sets of 2 for $12.95 each. How much will purchasing these products cost?

Correct answer: B

Rationale: To find the total cost, first calculate the cost of pens and staplers separately. 240 pens require 40 packs (240 pens ÷ 6 pens per pack = 40 packs). Each pack of pens costs $2.35, so 40 packs cost $94 (40 packs × $2.35 per pack = $94). For the staplers, 6 staplers require 3 packs (6 staplers ÷ 2 staplers per pack = 3 packs). Each pack of staplers costs $12.95, so 3 packs cost $38.85 (3 packs × $12.95 per pack = $38.85). Adding the cost of pens and staplers together gives a total of $132.85, which rounds to $132.00. Therefore, the correct answer is $132.00. Choice A is incorrect as it does not consider the individual prices of pens and staplers. Choice C is incorrect as it overestimates the total cost by combining the costs incorrectly. Choice D is incorrect as it underestimates the total cost by not considering both pens and staplers.

3. A diabetic patient's blood sugar is 180mg/dL. Their usual insulin dose is 1 unit per 40mg/dL above 100mg/dL. How much insulin should be administered?

Correct answer: B

Rationale: Rationale: 1. Calculate the excess blood sugar above 100mg/dL: 180mg/dL - 100mg/dL = 80mg/dL. 2. Determine the insulin dose based on the patient's usual insulin dose: 80mg/dL / 40mg/dL = 2 units. 3. Add the calculated insulin dose to the patient's usual insulin dose: 1 unit (usual dose) + 2 units (calculated dose) = 3 units. Therefore, the correct answer is 3 units of insulin should be administered to the diabetic patient with a blood sugar level of 180mg/dL.

4. A water fountain has a spherical base with a diameter of 50cm and a cylindrical body with a diameter of 30cm and a height of 80cm. What is the total surface area of the fountain (excluding the water surface)?

Correct answer: C

Rationale: To find the total surface area of the fountain, we first calculate the surface area of the sphere and the cylinder separately. For the sphere: - Radius = Diameter / 2 = 50 / 2 = 25 cm - Surface area of a sphere = 4πr² = 4 x π x 25² = 500π cm² For the cylinder: - Radius = Diameter / 2 = 30 / 2 = 15 cm - Surface area of a cylinder = 2πrh + 2πr² = 2 x π x 15 x 80 + 2 x π x 15² = 240π + 450π = 690π cm² Total surface area = Surface area of sphere + Surface area of cylinder = 500π + 690π = 1190π cm² ≈ 5486 sq cm. Therefore, the correct answer is C. Choice A (3142 sq cm) is incorrect as it is much smaller than the correct answer. Choices B and D are also incorrect as they do not reflect the accurate calculation of the total surface area of the fountain.

5. Reduce 5 & 3/4 divided by 1/2.

Correct answer: D

Rationale: To divide mixed numbers, convert them to improper fractions. 5 & 3/4 = 23/4 and 1/2 = 2/1. So, 23/4 ÷ 2/1 = 23/4 * 1/2 = 23/8 = 2 & 7/8. Therefore, 5 & 3/4 divided by 1/2 reduces to 11 & 1/2. Choices A, B, and C are incorrect because they do not represent the correct result of dividing 5 & 3/4 by 1/2.

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