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HESI A2

HESI A2 Practice Test Math

1. Add 2/3 + 4/9.

Correct answer: C

Rationale: To add the fractions, first find a common denominator. The least common denominator between 3 and 9 is 9. Convert 2/3 to 6/9 then add 6/9 + 4/9: = 10/9

2. How many milliliters are in 6 liters?

Correct answer: B

Rationale: The correct answer is B: 6000 milliliters. There are 1,000 milliliters in a liter. To convert liters to milliliters, you multiply the number of liters by 1,000. Therefore, 6 liters = 6 × 1,000 = 6,000 milliliters. Choices A, C, and D are incorrect because they do not correctly convert liters to milliliters.

3. How many milliliters are in 1 liter?

Correct answer: B

Rationale: There are 1,000 milliliters in 1 liter. The prefix 'milli-' means one-thousandth, so when converting from liters to milliliters, you multiply by 1,000. Therefore, the correct answer is 1,000 mL. Choice A (100 mL) is incorrect as it represents one-tenth of the correct conversion. Choice C (500 mL) is incorrect as it is half of the correct conversion. Choice D (50 mL) is incorrect as it is one-twentieth of the correct conversion.

4. What is the result of adding 1/2 + 4/5?

Correct answer: A

Rationale: To add fractions, you need a common denominator. In this case, the common denominator is 10. So, 1/2 + 4/5 = 5/10 + 8/10 = 13/10 = 1 3/10. Therefore, the correct answer is A: 1 3/10. Choice B, 1/2/2024, is incorrect as it does not represent the sum of the fractions given. Choice C, 1 2/5, is incorrect as it does not match the sum calculated. Choice D, 1 1/5, is incorrect as it does not reflect the correct sum of the fractions provided.

5. How much paint do you need to paint the interior walls and floor of a rectangular swimming pool with dimensions 8m by 5m and a depth of 2m? (Assume one can of paint covers 10 sq m)

Correct answer: C

Rationale: To calculate the total area to be painted, find the area of each wall and the floor, sum them up, and subtract the area of the top surface of the pool. The area to be painted is (2*8 + 2*5 + 8*5) = 16 + 10 + 40 = 66 sq m. Since one can of paint covers 10 sq m, divide the total area (66 sq m) by the coverage area per can to determine the number of cans needed. Therefore, you need 88 sq m of paint, which is equivalent to 9 cans of paint. Choice A, B, and D are incorrect as they do not represent the correct calculation of the total area to be painted.

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