HESI A2
HESI A2 Quizlet Math
1. What is the cost of building a fence around a square lawn with an area of 62,500 square meters at a rate of $5 per meter?
- A. $4,000
- B. $4,500
- C. $5,000
- D. $5,500
Correct answer: C
Rationale: To determine the cost of building a fence around the square lawn, first calculate the length of one side by finding the square root of the area: √62500 = 250 meters (length of one side). The perimeter of a square is four times the length of one side, so the perimeter of the lawn is 4 * 250 = 1000 meters. To find the cost of the fence, multiply the perimeter by the cost per meter: 1000 meters * $5/meter = $5000. Therefore, the correct answer is $5,000, which corresponds to choice C. Choice A ($4,000), choice B ($4,500), and choice D ($5,500) are incorrect as they do not accurately calculate the cost based on the given information.
2. Convert the decimal to a percent: 0.64
- A. 0.64%
- B. 6.4%
- C. 64%
- D. 0.064%
Correct answer: C
Rationale: To convert a decimal to a percent, you multiply by 100 or move the decimal point two places to the right. In this case, 0.64 becomes 64%. Therefore, the correct answer is 64%. Choice A, 0.64%, is incorrect because it does not convert the decimal to a percent. Choice B, 6.4%, is incorrect as it mistakenly moves the decimal point only one place. Choice D, 0.064%, is incorrect as it moves the decimal point three places instead of two.
3. What is the result of adding 12 1/21 and 3 1/3?
- A. 15 8/21
- B. 16 5/24
- C. 15
- D. 14
Correct answer: A
Rationale: To add 12 1/21 and 3 1/3, first add the whole numbers: 12 + 3 = 15. Then, add the fractions: 1/21 + 1/3. To find a common denominator, multiply 21 by 3 to get 63. Convert 1/21 to an equivalent fraction with a denominator of 63 by multiplying the numerator and denominator by 3, resulting in 3/63. Now add 3/63 (equivalent to 1/21) and 21/63 (equivalent to 1/3) to get 24/63. Simplifying 24/63 gives 8/21. Therefore, the sum is 15 8/21. Choices B, C, and D are incorrect because they do not result from the correct addition of the given numbers and fractions.
4. A water fountain has a spherical base with a diameter of 50cm and a cylindrical body with a diameter of 30cm and a height of 80cm. What is the total surface area of the fountain (excluding the water surface)?
- A. 3142 sq cm
- B. 4712 sq cm
- C. 5486 sq cm
- D. 7957 sq cm
Correct answer: C
Rationale: To find the total surface area of the fountain, we first calculate the surface area of the sphere and the cylinder separately. For the sphere: - Radius = Diameter / 2 = 50 / 2 = 25 cm - Surface area of a sphere = 4πr² = 4 x π x 25² = 500π cm² For the cylinder: - Radius = Diameter / 2 = 30 / 2 = 15 cm - Surface area of a cylinder = 2πrh + 2πr² = 2 x π x 15 x 80 + 2 x π x 15² = 240π + 450π = 690π cm² Total surface area = Surface area of sphere + Surface area of cylinder = 500π + 690π = 1190π cm² ≈ 5486 sq cm. Therefore, the correct answer is C. Choice A (3142 sq cm) is incorrect as it is much smaller than the correct answer. Choices B and D are also incorrect as they do not reflect the accurate calculation of the total surface area of the fountain.
5. In a class of 25 students, 44% are boys. How many boys are there?
- A. 10 boys
- B. 11 boys
- C. 9 boys
- D. 13 boys
Correct answer: B
Rationale: To find the number of boys in the class, calculate 44% of 25 students. 44% of 25 is calculated as follows: 0.44 x 25 = 11 boys. Therefore, there are 11 boys in the class. Choice A, 10 boys, is incorrect as it miscalculates the percentage. Choice C, 9 boys, is incorrect as it is less than 11. Choice D, 13 boys, is incorrect as it is greater than the correct calculation.
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