Nursing Elites

1. A solution is 60% alcohol. If 200ml of the solution is used, how much pure alcohol is present?

• A. 100ml
• B. 120ml
• C. 140ml
• D. 160ml

Correct answer: B

Rationale: If the solution is 60% alcohol, it means that 60% of the solution is alcohol. Therefore, in 200ml of the solution, the amount of alcohol present is: 200ml * 60% = 200ml * 0.60 = 120ml. So, when 200ml of the solution is used, there are 120ml of pure alcohol present. Choice A, 100ml, is incorrect because it does not account for the correct percentage of alcohol in the solution. Choice C, 140ml, and Choice D, 160ml, are incorrect as they overestimate the amount of pure alcohol present in the solution.

2. An IV bag contains 500ml of saline solution and needs to be infused over 4 hours. What is the flow rate in drops per minute, assuming 20 drops per milliliter?

• A. 12.5 drops/min
• B. 25 drops/min
• C. 50 drops/min
• D. 100 drops/min

Correct answer: C

Rationale: To find the flow rate in drops per minute, first, calculate the total volume in drops by multiplying the volume in milliliters by the number of drops per milliliter (500ml * 20 drops/ml = 10,000 drops). Then, divide this total number of drops by the infusion time in minutes (4 hours * 60 minutes/hour = 240 minutes) to get the flow rate. Therefore, the correct flow rate is 50 drops/min. Choice A is incorrect because it miscalculates the flow rate. Choice B is incorrect as it also miscalculates the flow rate. Choice D is incorrect as it overestimates the flow rate.

3. Your supervisor instructs you to purchase 240 pens and 6 staplers for the nurse's station. Pens are purchased in sets of 6 for $2.35 per pack. Staplers are sold in sets of 2 for $12.95 each. How much will purchasing these products cost?

• A. $162.00
• B. $132.00
• C. $225.00
• D. $145.00

Correct answer: B

Rationale: To find the total cost, first calculate the cost of pens and staplers separately. 240 pens require 40 packs (240 pens ÷ 6 pens per pack = 40 packs). Each pack of pens costs $2.35, so 40 packs cost $94 (40 packs × $2.35 per pack = $94). For the staplers, 6 staplers require 3 packs (6 staplers ÷ 2 staplers per pack = 3 packs). Each pack of staplers costs $12.95, so 3 packs cost $38.85 (3 packs × $12.95 per pack = $38.85). Adding the cost of pens and staplers together gives a total of $132.85, which rounds to $132.00. Therefore, the correct answer is $132.00. Choice A is incorrect as it does not consider the individual prices of pens and staplers. Choice C is incorrect as it overestimates the total cost by combining the costs incorrectly. Choice D is incorrect as it underestimates the total cost by not considering both pens and staplers.

4. Change 0.015 to a fraction.

• A. 3/200
• B. 3/2000
• C. 15/1000
• D. 3/100

Correct answer: A

Rationale: To convert 0.015 to a fraction, we can rewrite it as 15/1000. Simplifying this fraction, we get 3/200. Therefore, the correct answer is A. Choice B (3/2000) is incorrect as the decimal 0.015 is equivalent to 15/1000, not 15/2000. Choice C (15/1000) is the initial form of 0.015 as a fraction, but it can be further simplified to 3/200. Choice D (3/100) is incorrect as it does not represent the decimal 0.015.

5. A lab needs 200ml of a 5% salt solution. They only have a 10% solution. How much 10% solution and water should be mixed?

• A. 100ml 10% solution, 100ml water
• B. 150ml 10% solution, 50ml water
• C. 160ml 10% solution, 40ml water
• D. 200ml 10% solution, 0ml water

Correct answer: B

Rationale: Rationale: 1. Let x be the volume of the 10% solution needed and y be the volume of water needed. 2. The total volume of the final solution is 200ml, so x + y = 200. 3. The concentration of the final solution is 5%, so the amount of salt in the final solution is 0.05 * 200 = 10g. 4. The amount of salt in the 10% solution is 0.1x, and the amount of salt in the water is 0, so the total amount of salt in the final solution is 0.1x. 5. Since the total amount of salt in the final solution is 10g, we have 0.1x = 10. 6. Solving for x, we get x = 100ml. 7. Substituting x =

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