a roast was cooked at 325f in the oven for 4 hours the internal temperature rose from 32f to 145f what was the average rise in temperature per hour

HESI A2

HESI A2 Practice Test Math

1. A roast was cooked at 325°F in the oven for 4 hours. The internal temperature rose from 32°F to 145°F. What was the average rise in temperature per hour?

A. 20
B. 32
C. 28
D. 37°F/hr

Correct answer: C

Rationale: The temperature increased from 32°F to 145°F, resulting in a total increase of 145°F - 32°F = 113°F. Dividing this total increase by the 4 hours of cooking time gives an average rise of 113°F ÷ 4 = 28.25°F per hour, which can be rounded to 28°F per hour. Therefore, the correct answer is 28. Choice A (20) is incorrect because it does not reflect the actual average rise in temperature per hour. Choice B (32) is incorrect as it does not consider the total temperature increase and divide it by the total hours. Choice D (37°F/hr) is incorrect as it does not match the calculated average rise in temperature per hour.

2. There are 6,657 marbles in a jar. Approximately 34% are white, and the rest are black. How many black marbles are there?

A. 4,394
B. 4,000
C. 3,000
D. 5,000

Correct answer: A

Rationale: To find the number of black marbles, we need to calculate the percentage that represents the black marbles, which is 100% - 34% = 66%. Then, we find 66% of 6,657 to determine the number of black marbles. 66% of 6,657 is approximately 4,394, so there are 4,394 black marbles in the jar. Choice A is correct. Choices B, C, and D are incorrect as they do not reflect the correct calculation for the number of black marbles in the jar.

3. Solve: 8x = x^2.

A. 6
B. 4
C. 16
D. 14

Correct answer: C

Rationale: To solve the equation 8x = x^2, rearrange it to x^2 - 8x = 0. Factor out an x to get x(x - 8) = 0. Set each factor to zero to find the solutions: x = 0 or x = 8. Therefore, x = 16 is the correct answer because x = 0 is not in the answer choices, and x = 8 is a distraction meant to confuse. Thus, choice C, 16, is the correct solution to the equation.

4. Temperature Conversion & Interpretation: A patient's body temperature is 102°F. Convert this to °C and assess if it indicates a fever.

A. 37�C (Normal)
B. 39�C (Low-grade fever)
C. 39�C (Fever)
D. 42�C (Hyperthermia)

Correct answer: C

Rationale: Rationale: 1. To convert Fahrenheit to Celsius, you can use the formula: °C = (°F - 32) x 5/9. 2. Given that the patient's body temperature is 102°F, we can calculate the equivalent temperature in Celsius: °C = (102 - 32) x 5/9 °C = 70 x 5/9 °C = 350/9 °C ≈ 38.9°C, which can be rounded to 39°C. 3. A body temperature of 39°C is considered to indicate a fever. Normal body temperature typically ranges from 36.1°C to 37.2°C, so a temperature of 39°C is higher than the normal range and suggests a fever. 4. Options A and B are incorrect as they do not reflect the conversion of 102°F to °C

5. A nurse is reviewing the daily intake and output (I&O) of a patient consuming a clear diet. The drainage bag denotes a total of 1,000 mL for the past 24 hours. The total intake is: 2 8oz cups of coffee, 1 16-oz serving of clear soup, and 1 pint of water consumed throughout the day. How much is the deficit in milliliters?

A. 440 mL
B. 500 mL
C. 480 mL
D. 300 mL

Correct answer: A

Rationale: First, convert all fluid intake to milliliters: 2 8-oz cups of coffee = 8 × 2 × 30 = 480 mL 1 16-oz serving of clear soup = 16 × 30 = 480 mL 1 pint of water = 16 × 30 = 480 mL Total intake = 480 + 480 + 480 = 1440 mL. The patient produced 1,000 mL, so the deficit is: 1440 mL - 1000 mL = 440 mL. Therefore, the deficit in milliliters is 440 mL. Choice A is correct. Choices B, C, and D are incorrect as they do not reflect the accurate deficit calculated based on the total intake and output provided in the question.