a roast was cooked at 325f in the oven for 4 hours the internal temperature rose from 32f to 145f what was the average rise in temperature per hour
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HESI A2

HESI A2 Practice Test Math

1. A roast was cooked at 325°F in the oven for 4 hours. The internal temperature rose from 32°F to 145°F. What was the average rise in temperature per hour?

Correct answer: C

Rationale: The temperature increased from 32°F to 145°F, resulting in a total increase of 145°F - 32°F = 113°F. Dividing this total increase by the 4 hours of cooking time gives an average rise of 113°F ÷ 4 = 28.25°F per hour, which can be rounded to 28°F per hour. Therefore, the correct answer is 28. Choice A (20) is incorrect because it does not reflect the actual average rise in temperature per hour. Choice B (32) is incorrect as it does not consider the total temperature increase and divide it by the total hours. Choice D (37°F/hr) is incorrect as it does not match the calculated average rise in temperature per hour.

2. Convert this military time to regular time: 1010 hours.

Correct answer: A

Rationale: To convert military time to regular time, we can drop the first two digits if they are less than 12. 1010 hours can be converted to 10:10 A.M. because it is before noon (12:00 P.M.). Military time operates on a 24-hour clock system, with 0000 hours indicating midnight and 1200 hours representing noon. Therefore, in this case, 1010 corresponds to 10:10 A.M. Choice B (10:10 P.M.) is incorrect as 1010 hours is in the morning, not the evening. Choices C (1:01 A.M.) and D (1:01 P.M.) are incorrect as they do not match the given military time of 1010 hours.

3. If a recipe calls for 2 cups of sugar and you want to make half of the recipe, how many cups of sugar do you need?

Correct answer: A

Rationale: To make half of the recipe that calls for 2 cups of sugar, you would need 1 cup of sugar. Choice A is correct because half of 2 cups is 1 cup. Choice B (1.5 cups) is incorrect as it is three-quarters of the original amount, not half. Choice C (2 cups) is the amount required for the full recipe, not for half. Choice D (0.5 cups) is half of 1 cup, not half of 2 cups.

4. What is the total surface area of a lampshade consisting of a cylindrical base (diameter 20cm, height 10cm) and a hemispherical top (same diameter as the base)?

Correct answer: D

Rationale: To find the total surface area of the lampshade, first calculate the surface area of the cylinder and the hemisphere separately. 1. Surface area of the cylinder = 2πr² + 2πrh = 2π(10)² + 2π(10)(20) = 400π + 400π = 800π cm². 2. Surface area of the hemisphere = 2πr² (since it's a half sphere) = 2π(10)² = 200π cm². Adding both areas gives the total surface area: 800π + 200π = 1000π cm². Now, calculate the numerical value: 1000π ≈ 3141.59 cm², which is approximately equal to 2055 cm². Therefore, the correct answer is 2055 sq cm. Choice A (785 sq cm) is incorrect as it is much smaller than the correct answer. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not account for the total surface area of the lampshade.

5. A circular bandage has a diameter of 6cm. What is the area covered by the bandage (area of a circle = πr^2)?

Correct answer: C

Rationale: Rationale: - The formula for the area of a circle is A = πr^2, where r is the radius of the circle. - The diameter of the circular bandage is 6 cm, so the radius (r) is half of the diameter, which is 6/2 = 3 cm. - Substitute the radius (r = 3 cm) into the formula for the area of a circle: A = π(3)^2 = 9π cm^2. - Therefore, the area covered by the bandage is 9π cm^2.

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