Nursing Elites

1. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

2. Before meiosis, a sperm cell:

• A. contains 46 chromosomes.
• B. contains two X chromosomes.
• C. is significantly larger than an egg cell.
• D. contains both an X and a Y chromosome.

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

3. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?

• A. The mother is Rh positive, and the father is Rh negative
• B. The mother is Rh negative, and the father is Rh positive
• C. The mother and the father are both Rh positive
• D. The mother and the father are both Rh negative

Correct answer: B

Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.

4. A nurse on an antepartum unit is reviewing the medical records for four clients. Which of the following clients should the nurse assess first?

• A. A client who has diabetes mellitus and an HbA1c of 5.8%
• B. A client who has preeclampsia and a creatinine level of 1.1 mg/dL
• C. A client who has hyperemesis gravidarum and a sodium level of 110 mEq/L
• D. A client who has placenta previa and a hematocrit of 36%

Correct answer: C

Rationale: A sodium level of 110 mEq/L is critically low and can indicate severe dehydration and electrolyte imbalance, requiring immediate intervention.

5. A woman gave birth to a 7-pound, 6-ounce infant girl 1 hour ago. The birth was vaginal and the estimated blood loss (EBL) was 1500 ml. When evaluating the woman’s vital signs, which finding would be of greatest concern to the nurse?

• A. Temperature 37.9°C, heart rate 120 beats per minute (bpm), respirations 20 breaths per minute, and blood pressure 90/50 mm Hg.
• B. Temperature 37.4°C, heart rate 88 bpm, respirations 36 breaths per minute, and blood pressure 126/68 mm Hg.
• C. Temperature 38°C, heart rate 80 bpm, respirations 16 breaths per minute, and blood pressure 110/80 mm Hg.
• D. Temperature 36.8°C, heart rate 60 bpm, respirations 18 breaths per minute, and blood pressure 140/90 mm Hg.

Correct answer: A

Rationale: An estimated blood loss (EBL) of 1500 ml following a vaginal birth is significant and can lead to hypovolemia. The vital signs provided in option A (Temperature 37.9°C, heart rate 120 bpm, respirations 20 breaths per minute, and blood pressure 90/50 mm Hg) indicate tachycardia and hypotension, which are concerning signs of hypovolemia due to excessive blood loss. Tachycardia is the body's compensatory mechanism to maintain cardiac output in response to decreased blood volume, and hypotension indicates inadequate perfusion. Options B, C, and D do not exhibit the same level of concern for hypovolemia. Option B shows tachypnea, which can be a result of pain or anxiety postpartum. Option C and D have vital signs within normal limits, which are not indicative of the body's response to significant blood loss.

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