Nursing Elites

1. After mitosis, the genetic code is identical in new cells unless _________ occur through radiation or other environmental influences.

• A. reductions
• B. expulsions
• C. conceptions
• D. mutations

Correct answer: D

Rationale: After mitosis, the genetic code is typically preserved and remains identical in the new cells. However, mutations can occur due to radiation or environmental influences, leading to changes in the DNA sequence and potentially altering the genetic code. Therefore, the correct answer is 'mutations.' Choices A, B, and C are incorrect because reductions, expulsions, and conceptions do not accurately describe the changes in the genetic code that can result from external factors. Mutations are the only option that reflects the alteration in the genetic code caused by external influences, making it the correct choice in this context.

2. A primigravida is being monitored at the prenatal clinic for preeclampsia. Which finding is of greatest concern to the nurse?

• A. Blood pressure (BP) increased to 138/86 mm Hg.
• B. Weight gain of 0.5 kg during the past 2 weeks.
• C. Dipstick value of 3+ for protein in her urine.
• D. Pitting pedal edema at the end of the day.

Correct answer: C

Rationale: The correct answer is C. Proteinuria, indicated by a dipstick value of 3+ in the urine, is a significant concern in a patient being monitored for preeclampsia. Proteinuria is a key diagnostic criterion for preeclampsia, and a value of 3+ signifies a substantial amount of protein in the urine, warranting further evaluation. While an increase in blood pressure to 138/86 mm Hg is slightly elevated, it does not meet the diagnostic threshold for severe hypertension in preeclampsia. A weight gain of 0.5 kg over 2 weeks is within normal limits and not as concerning as significant rapid weight gain. Pitting pedal edema, though common in pregnancy, is not a specific indicator of preeclampsia and is considered a less concerning finding compared to significant proteinuria.

3. The healthcare provider prescribes 10 units per liter of oxytocin via IV drip to augment a client's labor because she is experiencing a prolonged active phase. Which finding would cause the nurse to immediately discontinue the oxytocin?

• A. Contraction duration of 100 seconds.
• B. Four contractions in 10 minutes.
• C. Uterus is soft.
• D. Early deceleration of fetal heart rate.

Correct answer: A

Rationale: A contraction duration of 100 seconds is too long and can indicate uterine hyperstimulation, which can lead to fetal distress and other complications. This prolonged contraction duration suggests that the uterus is not relaxing adequately between contractions, potentially compromising fetal oxygenation. Choice B, 'Four contractions in 10 minutes,' is a sign of tachysystole, which is concerning but not as immediately critical as the prolonged contraction duration. Choice C, 'Uterus is soft,' is not a reason to discontinue oxytocin; in fact, it is a normal finding. Choice D, 'Early deceleration of fetal heart rate,' while indicating fetal distress, is not a direct result of the oxytocin and may require intervention but not immediate discontinuation of the medication.

4. According to a study conducted in 2013 by Fellman, what affects the chances of having twins?

• A. Increase when a woman conceives at a younger age.
• B. Increase with parental age.
• C. Decrease with the frequency of intercourse before conception.
• D. Decrease with the use of fertility drugs.

Correct answer: B

Rationale: The correct answer is B. According to the study by Fellman in 2013, the chances of having twins actually increase with parental age. Choice A is incorrect as the study does not specify a younger age for conceiving to increase the chances of twins. Choice C is incorrect as the frequency of intercourse before conception is not a highlighted factor in the study. Choice D is also incorrect as the study does not discuss the impact of fertility drugs on the likelihood of having twins.

5. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?

• A. The mother is Rh positive, and the father is Rh negative
• B. The mother is Rh negative, and the father is Rh positive
• C. The mother and the father are both Rh positive
• D. The mother and the father are both Rh negative

Correct answer: B

Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.

Similar Questions