a nurse is providing teaching about expected changes during pregnancy to a client who is at 24 weeks of gestation which of the following information s
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Maternity HESI Practice Questions

1. A client who is at 24 weeks of gestation is receiving teaching about expected changes during pregnancy. Which of the following information should the nurse include?

Correct answer: C

Rationale: Nasal stuffiness is a common symptom during pregnancy due to increased blood flow and hormonal changes. This symptom is caused by the increased blood volume and hormonal changes that lead to swelling of the nasal passages. Choices A, B, and D are incorrect. Stomach emptying rate does not significantly change during pregnancy; the uterus does not double in size at 24 weeks but rather grows steadily, and nipples typically darken in color due to increased pigmentation.

2. Before meiosis, a sperm cell:

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

3. Dizygotic (DZ) twins share _________ percent of their genes.

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

4. The nurse is caring for a multiparous client who is 8 centimeters dilated, 100% effaced, and the fetal head is at 0 station. The client is shivering and states extreme discomfort with the urge to bear down. Which intervention should the nurse implement?

Correct answer: C

Rationale: Repositioning the client to a side-lying position is the most appropriate intervention in this scenario. This position can help relieve pressure on the cervix and reduce the urge to push prematurely, allowing the cervix to continue dilating. Administering IV pain medication may not address the underlying cause of the discomfort, and pushing prematurely can lead to cervical trauma. Performing a vaginal exam is not necessary at this point as the client is already 8 centimeters dilated, and the fetal head is at 0 station.

5. After mitosis, the genetic code is identical in new cells unless _________ occur through radiation or other environmental influences.

Correct answer: D

Rationale: After mitosis, the genetic code is typically preserved and remains identical in the new cells. However, mutations can occur due to radiation or environmental influences, leading to changes in the DNA sequence and potentially altering the genetic code. Therefore, the correct answer is 'mutations.' Choices A, B, and C are incorrect because reductions, expulsions, and conceptions do not accurately describe the changes in the genetic code that can result from external factors. Mutations are the only option that reflects the alteration in the genetic code caused by external influences, making it the correct choice in this context.

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