Nursing Elites

1. What determines a child’s sex?

• A. Presence of teratogens at the time of conception.
• B. Sex chromosome received from the mother.
• C. Presence of teratogens at the time of ovulation.
• D. Sex chromosome received from the father.

Correct answer: D

Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.

2. A nurse on the labor and delivery unit is assessing four clients. Which of the following clients is a candidate for an induction of labor with misoprostol?

• A. A client who has active genital herpes
• B. A client who has gestational diabetes mellitus
• C. A client who has a previous uterine incision
• D. A client who has placenta previa

Correct answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.

3. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?

• A. The mother is Rh positive, and the father is Rh negative
• B. The mother is Rh negative, and the father is Rh positive
• C. The mother and the father are both Rh positive
• D. The mother and the father are both Rh negative

Correct answer: B

Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.

4. When children who are reared by adoptive parents are nonetheless more similar to their natural parents in a trait, it can be concluded that:

• A. the genetic characteristics of the children change over time.
• B. heredity is solely responsible for how a child grows.
• C. the environment is solely responsible for the development of those characteristics.
• D. genetics play a role in the development of those characteristics.

Correct answer: D

Rationale: When children exhibit traits that are more similar to their biological parents than their adoptive parents, it indicates a strong genetic influence on those traits. This similarity suggests that genetics play a significant role in the development of the observed characteristics. Choice A is incorrect because genetic characteristics do not change over time in this context. Choice B is incorrect as it implies that heredity is the only factor, disregarding the impact of the environment. Choice C is also incorrect as it suggests that only the environment influences trait development, overlooking the genetic contribution.

5. In the Ballard Gestational Age Assessment Tool, the nurse determines that a 15-month-old infant has a gestational age of 42 weeks. Based on this finding, which intervention is most important for the nurse to implement?

• A. Provide blow-by oxygen
• B. Provide a capillary blood glucose test
• C. Draw arterial blood gases
• D. Apply a pulse oximeter to the foot

Correct answer: B

Rationale: Late preterm infants, such as those with a gestational age of 42 weeks, are at higher risk for hypoglycemia due to immature metabolic regulation. Monitoring capillary blood glucose is crucial to detect and manage hypoglycemia promptly. Providing blow-by oxygen (Choice A) is not indicated for an infant at risk for hypoglycemia. Drawing arterial blood gases (Choice C) is not the primary intervention for assessing hypoglycemia. Applying a pulse oximeter to the foot (Choice D) is not directly related to monitoring blood glucose levels in this context.

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