Nursing Elites

1. A 16-year-old gravida 1 para 0 client has just been admitted to the hospital with a diagnosis of eclampsia. She's not presently convulsing. Which intervention should the nurse plan to include in this client's nursing care plan?

• A. Allow liberal family visitation
• B. Keep an airway at the bedside
• C. Assess temperature every hour
• D. Monitor blood pressure, pulse, and respiration every 4 hours

Correct answer: B

Rationale: Keeping an airway at the bedside is crucial for a client with eclampsia, as there is a high risk of seizures that can obstruct the airway. Allowing liberal family visitation (choice A) may not be a priority at this time and can be overwhelming for the client. Assessing temperature every hour (choice C) is not directly related to managing eclampsia. Monitoring blood pressure, pulse, and respiration every 4 hours (choice D) is important but not as immediate as ensuring airway patency.

2. The client who is 40 weeks gestation seems upset and tells the nurse that the physician told her she needs to have a nonstress test. The client asks why she needs the test. The nurse’s best response would be:

• A. This is a test to see if your stress level is affecting your baby’s growth and well-being.
• B. This is a test to see if your baby will be able to withstand the stress of labor.
• C. This is a test to assess your baby’s well-being now that you are due to deliver soon.
• D. This is a test to let us know if your baby needs to be delivered to avoid a bad outcome.

Correct answer: C

Rationale: The correct response is C because the nonstress test is specifically used to assess the baby's well-being close to the due date. It helps determine if the baby is receiving enough oxygen and nutrients in the womb. Choice A is incorrect as the test does not assess the mother's stress level but focuses on fetal well-being. Choice B is incorrect as the test does not predict the baby's ability to withstand labor. Choice D is incorrect because the test does not solely indicate if the baby needs to be delivered to avoid a bad outcome; rather, it assesses the current well-being of the baby.

3. A client is in the second stage of labor. Which of the following manifestations should the nurse expect?

• A. The client expels the placenta
• B. The client experiences gradual dilation of the cervix
• C. The client begins having regular contractions
• D. The client delivers the newborn

Correct answer: D

Rationale: During the second stage of labor, the cervix is fully dilated, and the client delivers the newborn. The expulsion of the placenta occurs during the third stage of labor, not the second stage. Regular contractions typically begin in the first stage of labor, not the second. Gradual dilation of the cervix occurs during the first stage of labor, specifically during the active phase.

4. A client has bacterial vaginosis. Which of the following medications should the nurse expect to administer?

• A. Metronidazole
• B. Fluconazole
• C. Acyclovir
• D. Clindamycin

Correct answer: A

Rationale: Metronidazole is the correct choice for treating bacterial vaginosis as it is the first-line medication recommended for this condition. Metronidazole works by disrupting the DNA structure of bacteria, making it an effective treatment. Choice B, Fluconazole, is an antifungal medication primarily used for treating fungal infections, not bacterial vaginosis. Choice C, Acyclovir, is an antiviral medication used to treat viral infections, not bacterial vaginosis. Choice D, Clindamycin, is also used to treat bacterial infections but is not the first-line treatment for bacterial vaginosis, making it an incorrect choice in this scenario.

5. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

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