Nursing Elites

1. A client is experiencing sore nipples from breastfeeding. Which of the following actions should the nurse take?

• A. Place a snug dressing on the client’s nipple when not breastfeeding
• B. Ensure the newborn’s mouth is wide open before latching to the breast
• C. Encourage the client to limit the newborn’s feeding to 10 minutes on each breast
• D. Instruct the client to begin the feeding with the nipple that is most tender

Correct answer: B

Rationale: Ensuring the newborn's mouth is wide open before latching is crucial for achieving a proper latch, which can help reduce nipple soreness. Placing a snug dressing on the nipple when not breastfeeding (choice A) can lead to further irritation and hinder healing. Encouraging the client to limit the newborn’s feeding to 10 minutes on each breast (choice C) may not be adequate for effective feeding as infants should feed until they are satisfied. Instructing the client to begin feeding with the most tender nipple (choice D) can worsen the soreness as it may not allow the baby to feed effectively.

2. Does a blastocyst gain mass only when it receives nourishment from outside?

• A. TRUE
• B. FALSE
• C. Sometimes
• D. Always

Correct answer: A

Rationale: A blastocyst does indeed require external nourishment from the mother's body to continue developing and gaining mass. Without this external nourishment, the blastocyst would not be able to grow and develop properly. Therefore, the statement that a blastocyst gains mass only when it receives nourishment from outside is true. Choices B, C, and D are incorrect because they do not accurately reflect the dependency of a blastocyst on external nourishment for its development and growth.

3. After a mother was diagnosed with gonorrhea immediately after delivery, what is an important goal of the nurse when providing care for her baby?

• A. Prevent the development of ophthalmia neonatorum.
• B. Lubricate the eyes.
• C. Prevent the development of infection.
• D. Teach about the risks of breastfeeding with gonorrhea.

Correct answer: A

Rationale: The correct answer is A: Prevent the development of ophthalmia neonatorum. When a mother has gonorrhea, the baby can be infected during delivery, leading to ophthalmia neonatorum, which can cause permanent blindness. Therefore, it is crucial for the nurse to prevent this condition by treating the baby's eyes with an antibiotic prophylactically after birth. Choice B, lubricating the eyes, is not the primary goal in this situation as preventing infection takes precedence. Choice C, preventing the development of infection, is too broad and does not specifically address the potential complication of ophthalmia neonatorum. Choice D, teaching about the risks of breastfeeding with gonorrhea, is important but not the immediate goal in this scenario where preventing ophthalmia neonatorum and potential blindness is the priority.

4. A multiparous client at 36 hours postpartum reports increased bleeding and cramping. On examination, the nurse finds the uterine fundus 2 centimeters above the umbilicus. Which action should the nurse take first?

• A. Increase the intravenous fluid to 150 ml/hr.
• B. Call the healthcare provider.
• C. Encourage the client to void.
• D. Administer ibuprofen 800 milligrams by mouth.

Correct answer: C

Rationale: Encouraging the client to void is the priority action in this scenario. A distended bladder can prevent the uterus from contracting properly, leading to increased bleeding and a high uterine fundus. By encouraging the client to void, the nurse can help the uterus contract effectively, reducing bleeding. Increasing intravenous fluids or administering ibuprofen would not address the immediate concern of a distended bladder affecting uterine contraction. While it may be necessary to involve the healthcare provider, addressing the bladder distention promptly is crucial to prevent further complications.

5. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

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