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HESI A2

HESI A2 Math Practice Test 2024

1. 5\7 + 3\14 = ?

Correct answer: A

Rationale: To add fractions with different denominators, first find a common denominator. The least common denominator between 7 and 14 is 14. Convert 5/7 to 10/14: 5 / 7 = 10 / 14 5/7=10/14 Now add the two fractions: 10 / 14 + 3 / 14 = 13 / 14 10/14+3/14=13/14

2. A kite has a top base of 20cm, a bottom base of 30cm, and two equal side lengths of 15cm. What is its perimeter?

Correct answer: C

Rationale: To find the perimeter of a kite, you need to add the lengths of all its sides. In this case, the perimeter is calculated as the sum of the top base, bottom base, and twice the side length. Therefore, perimeter = top base + bottom base + 2 * side length = 20cm + 30cm + 2 * 15cm = 70cm. Choice A, B, and D are incorrect as they do not consider all sides of the kite in the calculation.

3. Farmer Juan finds that it takes 2 chickens to produce 6 eggs in 24 hours. How many chickens are needed to produce 24 eggs in 24 hours?

Correct answer: C

Rationale: If 2 chickens produce 6 eggs in 24 hours, to produce 24 eggs in the same time frame, you would need 8 chickens. Therefore, Choice C is correct. Choice A (48) is incorrect because it miscalculates the number of chickens required. Choice B (18) is incorrect as it does not consider the proportional relationship between chickens and eggs. Choice D (6) is incorrect as it doesn't account for the increased number of eggs.

4. What is the least common multiple (LCM) of 4 and 6?

Correct answer: A

Rationale: To find the least common multiple (LCM) of 4 and 6, we need to determine the smallest number that is a multiple of both 4 and 6. The multiples of 4 are: 4, 8, 12, 16, 20, 24, ... The multiples of 6 are: 6, 12, 18, 24, ... The least common multiple is the smallest number that appears in both lists. In this case, the least common multiple of 4 and 6 is 12, not 24. Therefore, the correct answer is 24. Choice B (12) is actually the least common multiple of 4 and 3, not 4 and 6. Choices C (6) and D (3) are not multiples of both 4 and 6, so they are incorrect.

5. A diabetic patient's blood sugar is 180mg/dL. Their usual insulin dose is 1 unit per 40mg/dL above 100mg/dL. How much insulin should be administered?

Correct answer: B

Rationale: Rationale: 1. Calculate the excess blood sugar above 100mg/dL: 180mg/dL - 100mg/dL = 80mg/dL. 2. Determine the insulin dose based on the patient's usual insulin dose: 80mg/dL / 40mg/dL = 2 units. 3. Add the calculated insulin dose to the patient's usual insulin dose: 1 unit (usual dose) + 2 units (calculated dose) = 3 units. Therefore, the correct answer is 3 units of insulin should be administered to the diabetic patient with a blood sugar level of 180mg/dL.

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