Nursing Elites

1. When both of the alleles for a trait, such as hair color, are the same, the person is said to be _____ for that trait.

• A. monozygous
• B. dizygous
• C. homozygous
• D. hemizygous

Correct answer: C

Rationale: A person is homozygous for a trait when they have two identical alleles for that trait. In this case, both alleles are the same, indicating a homozygous genotype. Choice A, 'monozygous,' is incorrect as it refers to identical twins originating from a single fertilized egg. Choice B, 'dizygous,' is also incorrect as it refers to fraternal twins or individuals that develop from two separate fertilized eggs. Choice D, 'hemizygous,' is incorrect because it describes a genetic condition where only one allele is present in a diploid organism, typically related to genes on the sex chromosomes.

2. When both alleles' effects are shown, there is said to be:

• A. codominance.
• B. preponderance.
• C. ascendance.
• D. concurrence.

Correct answer: A

Rationale: The correct answer is A: codominance. Codominance refers to a genetic scenario where both alleles in a gene pair are fully expressed, leading to a phenotype that displays traits from both alleles equally. This is distinct from incomplete dominance where the traits blend. Choices B, C, and D are incorrect. Preponderance does not specifically relate to the expression of alleles. Ascendance and concurrence do not describe the genetic concept of codominance where both alleles are fully expressed.

3. A nurse is caring for a newborn who is 6 hours old and has a bedside glucometer reading of 65 mg/dL. The newborn’s mother has type 2 diabetes mellitus. Which of the following actions should the nurse take?

• A. Obtain a blood sample for a serum glucose level
• B. Feed the newborn immediately
• C. Administer 50 mL of dextrose solution IV
• D. Reassess the blood glucose level prior to the next feeding

Correct answer: D

Rationale: A bedside glucometer reading of 65 mg/dL is within the normal range for a newborn. Reassessing the blood glucose level prior to the next feeding ensures ongoing monitoring without unnecessary intervention. Obtaining a blood sample for a serum glucose level (Choice A) is not necessary as the initial reading is normal. Feeding the newborn immediately (Choice B) may not be indicated and could lead to unnecessary interventions. Administering dextrose solution IV (Choice C) is not warranted as the glucose level is within the normal range and does not require immediate correction.

4. What determines a child’s sex?

• A. Presence of teratogens at the time of conception.
• B. Sex chromosome received from the mother.
• C. Presence of teratogens at the time of ovulation.
• D. Sex chromosome received from the father.

Correct answer: D

Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.

5. In contrast to placenta previa, what is the most prevalent clinical manifestation of abruptio placentae?

• A. Bleeding.
• B. Intense abdominal pain.
• C. Uterine activity.
• D. Cramping.

Correct answer: B

Rationale: The correct answer is B: Intense abdominal pain. Pain is absent with placenta previa but can be agonizing with abruptio placentae. While bleeding may be present in varying degrees for both placental conditions, intense abdominal pain is a distinguishing feature of abruptio placentae. Uterine activity and cramping may be present with both placental conditions, but they are not the most prevalent clinical manifestation of abruptio placentae.

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