Nursing Elites

1. Before meiosis, a sperm cell:

• A. contains 46 chromosomes.
• B. contains two X chromosomes.
• C. is significantly larger than an egg cell.
• D. contains both an X and a Y chromosome.

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

2. Which of the following pairs of bases is present in the rungs of the ladder-like structure of deoxyribonucleic acid (DNA)?

• A. Cytosine with guanine.
• B. Rhodamine with biotin.
• C. Diaminopurine with ribozyme.
• D. Serine with tyrosine.

Correct answer: A

Rationale: The correct answer is A: Cytosine with guanine. In the DNA double helix, cytosine always pairs with guanine forming a base pair, and adenine pairs with thymine. These complementary base pairs form the rungs of the ladder-like structure of DNA. Choice B, Rhodamine with biotin, is incorrect as they are not base pairs found in DNA. Choice D, Serine with tyrosine, is incorrect as they are amino acids, not DNA bases. Choice C, Diaminopurine with ribozyme, is also incorrect as ribozyme is an enzyme, not a base, and diaminopurine is not one of the standard bases found in DNA.

3. According to a survey by Adhikari and Liu in the year 2013, at birth, women have:

• A. close to 100,000 ova.
• B. around 300,000 to 400,000 ova.
• C. around 100 to 200 ova.
• D. only 500 ova.

Correct answer: B

Rationale: Women are born with approximately 300,000 to 400,000 ova, which gradually decrease in number as they age. Choice A ('close to 100,000 ova.') is incorrect as the actual number is much higher. Choice C ('around 100 to 200 ova.') is incorrect as it underestimates the quantity significantly. Choice D ('only 500 ova.') is incorrect as it greatly underestimates the number of ova present at birth.

4. At 31 weeks gestation, a client with a fundal height measurement of 25 cm is scheduled for a series of ultrasounds to be performed every two weeks. Which explanation should the nurse provide?

• A. Assessment for congenital anomalies
• B. Recalculation of gestational age
• C. Evaluation of fetal growth
• D. Determination of fetal presentation

Correct answer: C

Rationale: The correct answer is C: 'Evaluation of fetal growth.' A fundal height measurement smaller than expected may indicate intrauterine growth restriction (IUGR), requiring serial ultrasounds to monitor fetal growth. Assessing for congenital anomalies (choice A) is usually done through detailed anatomy scans earlier in pregnancy. Recalculating gestational age (choice B) is typically unnecessary at this stage unless there are concerns about accuracy. Determining fetal presentation (choice D) is usually done closer to term to plan for the mode of delivery.

5. The nurse is receiving a report for a laboring client who arrived in the emergency center with ruptured membranes that the client did not recognize. Which is the priority nursing action to implement when the client is admitted to the labor and delivery suite?

• A. Begin a pad count
• B. Prepare to start an IV
• C. Take the client's temperature
• D. Monitor amniotic fluid for meconium

Correct answer: C

Rationale: The priority nursing action when a client with ruptured membranes is admitted to the labor and delivery suite is to take the client's temperature. This is crucial to assess for infection, especially when the duration of membrane rupture is unknown. Beginning a pad count, preparing to start an IV, and monitoring amniotic fluid for meconium are important actions but are not as immediate or critical as assessing for infection through temperature measurement.

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