Nursing Elites

1. A woman with gestational diabetes has had little or no experience reading and interpreting glucose levels. The client shows the nurse her readings for the past few days. Which reading signals the nurse that the client may require an adjustment of insulin or carbohydrates?

• A. 75 mg/dl before lunch. This is low; better eat now.
• B. 115 mg/dl 1 hour after lunch. This is a little high; maybe eat a little less next time.
• C. 115 mg/dl 2 hours after lunch. This is too high; it is time for insulin.
• D. 50 mg/dl just after waking up from a nap. This is too low; maybe eat a snack before going to sleep.

Correct answer: D

Rationale: 50 mg/dl after waking from a nap is too low. During hours of sleep, glucose levels should not be less than 60 mg/dl. Snacks before sleeping can be helpful. The premeal acceptable range is 60 to 99 mg/dl. The readings 1 hour after a meal should be less than 129 mg/dl. Two hours after eating, the readings should be less than 120 mg/dl.

2. At 12 hours after the birth of a healthy infant, the mother complains of feeling constant vaginal pressure. The nurse determines the fundus is firm and at midline with moderate rubra lochia. Which action should the nurse take?

• A. Check the suprapubic area for distention
• B. Inform the client to take a warm sitz bath
• C. Inspect the client's perineal and rectal areas
• D. Apply a fresh pad and check in 1 hour

Correct answer: C

Rationale: In this situation, the mother's complaint of constant vaginal pressure along with a firm fundus and moderate rubra lochia indicates a potential perineal injury or hematoma. The correct action for the nurse to take is to inspect the client's perineal and rectal areas to assess for any signs of trauma or hematoma. Checking the suprapubic area for distention (Choice A) is not the priority here since the symptoms suggest a perineal issue. Advising a warm sitz bath (Choice B) may not address the underlying issue and could potentially worsen any existing trauma. Applying a fresh pad and checking in 1 hour (Choice D) does not address the need for immediate assessment of the perineal and rectal areas in response to the reported symptoms.

3. Monozygotic (MZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

4. A premature infant with respiratory distress syndrome (RDS) receives artificial surfactant. How does the nurse explain surfactant therapy to the parents?

• A. “Surfactant improves the ability of your baby’s lungs to exchange oxygen and carbon dioxide.”
• B. “The drug keeps your baby from requiring too much sedation.”
• C. “Surfactant is used to reduce episodes of periodic apnea.”
• D. “Your baby needs this medication to fight a possible respiratory tract infection.”

Correct answer: A

Rationale: Artificial surfactant can be administered as an adjunct to oxygen and ventilation therapy for premature infants with respiratory distress syndrome (RDS). It helps improve respiratory compliance by aiding in the exchange of oxygen and carbon dioxide until the infant can produce enough surfactant naturally. The correct explanation to the parents would be that surfactant therapy enhances the baby’s lung function by facilitating the exchange of oxygen and carbon dioxide. Choice B is incorrect because surfactant therapy does not affect sedation needs. Choice C is inaccurate as surfactant is not used to reduce episodes of periodic apnea. Choice D is incorrect as surfactant is not administered to fight respiratory tract infections; it specifically targets improving lung function in RDS.

5. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:

• A. a carrier of the recessive gene that causes the disease.
• B. susceptible to the disease after adolescence.
• C. an acceptor of the recessive gene that causes the disease.
• D. susceptible to the disease in late adulthood.

Correct answer: A

Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.

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