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Maternity HESI Test Bank
1. Which of the following statements is a symptom of cystic fibrosis in children?
- A. Cystic fibrosis leads to uncontrollable muscle movements and personality changes.
- B. Cystic fibrosis leads to the excessive production of thick mucus that clogs the pancreas and lungs.
- C. Cystic fibrosis causes red blood cells to clump together, obstructing small blood vessels and decreasing the oxygen supply.
- D. Cystic fibrosis causes the central nervous system to degenerate, resulting in death.
Correct answer: B
Rationale: The correct answer is B. Cystic fibrosis is a genetic disorder that causes the body to produce thick, sticky mucus. This mucus can clog the airways in the lungs and obstruct the pancreas, leading to severe respiratory and digestive problems. Choice A is incorrect because uncontrollable muscle movements and personality changes are not typical symptoms of cystic fibrosis. Choice C is incorrect because cystic fibrosis does not directly cause red blood cells to clump together and obstruct small blood vessels. Choice D is incorrect because cystic fibrosis primarily affects the respiratory and digestive systems, not the central nervous system.
2. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?
- A. A pattern of fetal late decelerations.
- B. Fetal heart rate accelerations with fetal movement.
- C. Absence of uterine contractions within 20 minutes.
- D. Spontaneous rupture of membranes.
Correct answer: A
Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.
3. Which of the following is a sexually transmitted infection that, in advanced stages, can attack major organ systems?
- A. Rubella
- B. Syphilis
- C. Cystic fibrosis
- D. Phenylketonuria
Correct answer: B
Rationale: Syphilis is the correct answer. Syphilis is a sexually transmitted infection caused by the bacterium Treponema pallidum. If left untreated, it can progress through various stages and potentially attack major organ systems, causing severe complications. Rubella, Cystic fibrosis, and Phenylketonuria are not sexually transmitted infections. Rubella is a viral infection, Cystic fibrosis is a genetic disorder affecting the lungs and digestive system, and Phenylketonuria is a genetic metabolic disorder. These conditions do not typically affect major organ systems in the same way as untreated syphilis.
4. A client is receiving an epidural block with an opioid analgesic. The nurse should monitor for which of the following findings as an adverse effect of the medication?
- A. Hypotension
- B. Polyuria
- C. Bilateral crackles
- D. Hyperglycemia
Correct answer: C
Rationale: The correct answer is C: Bilateral crackles. Bilateral crackles indicate respiratory complications, which can occur as an adverse effect of an epidural block with opioid analgesics. Hypotension (Choice A) is a common side effect of epidural opioids but is not typically monitored via crackles. Polyuria (Choice B) is excessive urination and is not directly associated with epidural blocks. Hyperglycemia (Choice D) is high blood sugar levels and is not a typical adverse effect of epidural opioids.
5. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:
- A. a carrier of the recessive gene that causes the disease.
- B. susceptible to the disease after adolescence.
- C. an acceptor of the recessive gene that causes the disease.
- D. susceptible to the disease in late adulthood.
Correct answer: A
Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.
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