HESI LPN
Maternity HESI Test Bank
1. Which of the following statements is a symptom of cystic fibrosis in children?
- A. Cystic fibrosis leads to uncontrollable muscle movements and personality changes.
- B. Cystic fibrosis leads to the excessive production of thick mucus that clogs the pancreas and lungs.
- C. Cystic fibrosis causes red blood cells to clump together, obstructing small blood vessels and decreasing the oxygen supply.
- D. Cystic fibrosis causes the central nervous system to degenerate, resulting in death.
Correct answer: B
Rationale: The correct answer is B. Cystic fibrosis is a genetic disorder that causes the body to produce thick, sticky mucus. This mucus can clog the airways in the lungs and obstruct the pancreas, leading to severe respiratory and digestive problems. Choice A is incorrect because uncontrollable muscle movements and personality changes are not typical symptoms of cystic fibrosis. Choice C is incorrect because cystic fibrosis does not directly cause red blood cells to clump together and obstruct small blood vessels. Choice D is incorrect because cystic fibrosis primarily affects the respiratory and digestive systems, not the central nervous system.
2. A newborn with a respiratory rate of 40 breaths per minute at one minute after birth is demonstrating cyanosis of the hands and feet. What action should a nurse take?
- A. Assess bowel sounds.
- B. Continue to monitor.
- C. Assist with intubation.
- D. Rub the infant's back.
Correct answer: B
Rationale: Cyanosis of the hands and feet, known as acrocyanosis, is common in newborns shortly after birth and usually resolves on its own. It is not indicative of a need for immediate intervention. Therefore, the appropriate action is to continue monitoring the newborn's condition. Assessing bowel sounds (Choice A) is not relevant to the presenting issue of cyanosis and respiratory rate. Assisting with intubation (Choice C) is an invasive procedure that is not warranted based on the information provided. Rubbing the infant's back (Choice D) is not necessary for acrocyanosis and could potentially disturb the newborn.
3. The mother of a breastfeeding 24-hour old infant is very concerned about the techniques involved in breastfeeding. She calls the nurse with each feeding to seek reassurance that she is doing it right. She tells the nurse, "Now my daughter is not getting enough to eat." Which response would be best for the nurse to make?
- A. Feed your baby hourly until you feel confident that your child is receiving enough milk.
- B. Don't worry, soon your milk will come in, and you will feel how full your breasts are.
- C. Since you are so concerned, you should probably supplement breastfeeding with formula.
- D. If your baby's urine is straw-colored, she's getting enough milk.
Correct answer: D
Rationale: Reassuring the mother that the baby's urine color can be an indicator of adequate hydration can help her feel more confident in her breastfeeding.
4. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?
- A. The mother is Rh positive, and the father is Rh negative
- B. The mother is Rh negative, and the father is Rh positive
- C. The mother and the father are both Rh positive
- D. The mother and the father are both Rh negative
Correct answer: B
Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.
5. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?
- A. Meconium-stained amniotic fluid
- B. Placenta previa
- C. Midline episiotomy
- D. Gestational hypertension
Correct answer: C
Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.
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