Nursing Elites

1. The nurse has received a report regarding a client in labor. The woman’s last vaginal examination was recorded as 3 cm, 30%, and –2. What is the nurse’s interpretation of this assessment?

• A. Cervix is effaced 3 cm and dilated 30%; the presenting part is 2 cm above the ischial spines.
• B. Cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm above the ischial spines.
• C. Cervix is effaced 3 cm and dilated 30%; the presenting part is 2 cm below the ischial spines.
• D. Cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm below the ischial spines.

Correct answer: B

Rationale: The correct interpretation of the assessment provided is that the cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm above the ischial spines. In the given assessment, the measurements are ordered as dilation, effacement, and station. Choice A is incorrect as it wrongly places the presenting part below the ischial spines. Choice C is incorrect because it places the presenting part below the ischial spines. Choice D is also incorrect as it incorrectly states that the presenting part is below the ischial spines, even though it correctly mentions the dilation and effacement of the cervix.

2. Which of the following statements is a characteristic of supermales?

• A. They are somewhat taller than average.
• B. Their facial hair growth is minimal when compared to normal males.
• C. They suffer from gynecomastia.
• D. They are typically impotent.

Correct answer: A

Rationale: The correct characteristic of supermales, individuals with an XYY chromosome pattern, is that they are somewhat taller than average. Choice B is incorrect as supermales do not exhibit minimal facial hair growth compared to normal males. Choice C is incorrect as gynecomastia, the development of male breasts, is not a characteristic of supermales. Choice D is also incorrect as impotence is not a typical characteristic associated with supermales.

3. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

4. Individuals with Klinefelter syndrome produce:

• A. less estrogen than normal males.
• B. less testosterone than normal males.
• C. less adenine than normal males.
• D. less thymine than normal males.

Correct answer: B

Rationale: Individuals with Klinefelter syndrome have an extra X chromosome (XXY), leading to reduced production of testosterone, the primary male sex hormone. This deficiency can result in various physical and developmental characteristics associated with the syndrome. Estrogen levels may actually be relatively elevated due to the imbalance between testosterone and estrogen. Choices C and D are incorrect as adenine and thymine are nucleotide bases found in DNA and are not related to hormone production.

5. What is the primary role of meiosis in the production of sperm and ova?

• A. To reduce the chromosome number by half
• B. To increase the chromosome number
• C. To create identical copies of chromosomes
• D. To repair damaged chromosomes

Correct answer: A

Rationale: The correct answer is A. Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the formation of sperm and ova. Choice B is incorrect because meiosis does not increase the chromosome number. Choice C is incorrect because meiosis creates genetically diverse gametes, not identical copies of chromosomes. Choice D is incorrect because meiosis does not primarily function to repair damaged chromosomes.

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