Nursing Elites

1. A newborn with a respiratory rate of 40 breaths per minute at one minute after birth is demonstrating cyanosis of the hands and feet. What action should a nurse take?

• A. Assess bowel sounds.
• B. Continue to monitor.
• C. Assist with intubation.
• D. Rub the infant's back.

Correct answer: B

Rationale: Cyanosis of the hands and feet, known as acrocyanosis, is common in newborns shortly after birth and usually resolves on its own. It is not indicative of a need for immediate intervention. Therefore, the appropriate action is to continue monitoring the newborn's condition. Assessing bowel sounds (Choice A) is not relevant to the presenting issue of cyanosis and respiratory rate. Assisting with intubation (Choice C) is an invasive procedure that is not warranted based on the information provided. Rubbing the infant's back (Choice D) is not necessary for acrocyanosis and could potentially disturb the newborn.

2. A healthcare provider is assessing a preterm newborn who is at 32 weeks of gestation. Which of the following finding should the healthcare provider expect?

• A. Minimal arm recoil
• B. Popliteal angle of less than 90°
• C. Creases over the entire sole
• D. Sparse lanugo

Correct answer: A

Rationale: When assessing a preterm newborn at 32 weeks of gestation, healthcare providers should expect minimal arm recoil. This finding is common in preterm infants due to lower muscle tone. Choice B, a popliteal angle of less than 90°, is incorrect for this age group. Creases over the entire sole (Choice C) typically develop at term age, not at 32 weeks of gestation. Sparse lanugo (Choice D) is a normal finding in preterm infants but is not specific to those at 32 weeks of gestation.

3. After mitosis, the genetic code is identical in new cells unless _________ occur through radiation or other environmental influences.

• A. reductions
• B. expulsions
• C. conceptions
• D. mutations

Correct answer: D

Rationale: After mitosis, the genetic code is typically preserved and remains identical in the new cells. However, mutations can occur due to radiation or environmental influences, leading to changes in the DNA sequence and potentially altering the genetic code. Therefore, the correct answer is 'mutations.' Choices A, B, and C are incorrect because reductions, expulsions, and conceptions do not accurately describe the changes in the genetic code that can result from external factors. Mutations are the only option that reflects the alteration in the genetic code caused by external influences, making it the correct choice in this context.

4. Monozygotic (MZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

5. Monozygotic (MZ) twins are known as fraternal twins.

• A. TRUE
• B. FALSE
• C. Possibly
• D. Never

Correct answer: B

Rationale: The correct answer is B: 'FALSE.' Monozygotic (MZ) twins are identical twins, not fraternal. Fraternal twins are dizygotic (DZ). The statement in the question is incorrect as MZ twins are genetically identical, while fraternal twins actually refer to dizygotic twins who develop from two separate fertilized eggs. Therefore, monozygotic twins are not known as fraternal twins, making option B the correct choice. Options A, C, and D are incorrect as they do not accurately describe the relationship between monozygotic and fraternal twins.

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