Nursing Elites

1. A newborn with a respiratory rate of 40 breaths per minute at one minute after birth is demonstrating cyanosis of the hands and feet. What action should a nurse take?

• A. Assess bowel sounds.
• B. Continue to monitor.
• C. Assist with intubation.
• D. Rub the infant's back.

Correct answer: B

Rationale: Cyanosis of the hands and feet, known as acrocyanosis, is common in newborns shortly after birth and usually resolves on its own. It is not indicative of a need for immediate intervention. Therefore, the appropriate action is to continue monitoring the newborn's condition. Assessing bowel sounds (Choice A) is not relevant to the presenting issue of cyanosis and respiratory rate. Assisting with intubation (Choice C) is an invasive procedure that is not warranted based on the information provided. Rubbing the infant's back (Choice D) is not necessary for acrocyanosis and could potentially disturb the newborn.

2. A premature infant with respiratory distress syndrome (RDS) receives artificial surfactant. How does the nurse explain surfactant therapy to the parents?

• A. “Surfactant improves the ability of your baby’s lungs to exchange oxygen and carbon dioxide.”
• B. “The drug keeps your baby from requiring too much sedation.”
• C. “Surfactant is used to reduce episodes of periodic apnea.”
• D. “Your baby needs this medication to fight a possible respiratory tract infection.”

Correct answer: A

Rationale: Artificial surfactant can be administered as an adjunct to oxygen and ventilation therapy for premature infants with respiratory distress syndrome (RDS). It helps improve respiratory compliance by aiding in the exchange of oxygen and carbon dioxide until the infant can produce enough surfactant naturally. The correct explanation to the parents would be that surfactant therapy enhances the baby’s lung function by facilitating the exchange of oxygen and carbon dioxide. Choice B is incorrect because surfactant therapy does not affect sedation needs. Choice C is inaccurate as surfactant is not used to reduce episodes of periodic apnea. Choice D is incorrect as surfactant is not administered to fight respiratory tract infections; it specifically targets improving lung function in RDS.

3. Preconception counseling is crucial for the safe management of diabetic pregnancies. Which complication is commonly associated with poor glycemic control before and during early pregnancy?

• A. Frequent episodes of maternal hypoglycemia
• B. Congenital anomalies in the fetus
• C. Hydramnios
• D. Hyperemesis gravidarum

Correct answer: B

Rationale: Preconception counseling is essential as strict metabolic control before conception and in the early weeks of gestation helps reduce the risk of congenital anomalies. Frequent episodes of maternal hypoglycemia usually occur during the first trimester due to hormonal changes, affecting insulin production and use, rather than before conception. Hydramnios is more common in diabetic pregnancies, typically seen in the third trimester, not during early pregnancy. Hyperemesis gravidarum, although it may lead to hypoglycemic events, is related to decreased food intake and glucose transfer to the fetus, exacerbating hypoglycemia rather than being directly associated with poor glycemic control before and during early pregnancy.

4. Is color blindness a sex-linked abnormality?

• A. TRUE
• B. FALSE
• C. Sometimes
• D. Always

Correct answer: A

Rationale: The correct answer is A: TRUE. Color blindness is indeed a sex-linked abnormality as it is often associated with genes on the X chromosome. Since males have only one X chromosome, they are more likely to inherit color blindness if the gene is present. This makes color blindness more common in males. Choice B (FALSE) is incorrect because color blindness is linked to the X chromosome. Choices C (Sometimes) and D (Always) are incorrect as color blindness is consistently tied to the X chromosome.

5. Monozygotic (MZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

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