Nursing Elites

1. On the first postpartum day, the nurse examines the breasts of a new mother. Which condition is the nurse most likely to find?

• A. Firm, larger, and very tender to the touch
• B. Slightly firm with an immediate let-down response
• C. Soft with no change from before delivery
• D. Filling and secreting colostrum

Correct answer: D

Rationale: On the first postpartum day, the nurse is most likely to find the breasts filling and secreting colostrum. Colostrum secretion is common as the body prepares for breastfeeding in the initial days after delivery. Choice A is incorrect as breasts are not typically very tender immediately postpartum. Choice B is incorrect as an immediate let-down response is more related to lactation rather than the first postpartum day. Choice C is incorrect as the breasts typically undergo changes, such as filling with colostrum, after delivery.

2. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

3. The nurse is caring for a multiparous client who is 8 centimeters dilated, 100% effaced, and the fetal head is at 0 station. The client is shivering and states extreme discomfort with the urge to bear down. Which intervention should the nurse implement?

• A. Administer IV pain medication
• B. Perform a vaginal exam
• C. Reposition to side-lying
• D. Encourage pushing with each contraction

Correct answer: C

Rationale: Repositioning the client to a side-lying position is the most appropriate intervention in this scenario. This position can help relieve pressure on the cervix and reduce the urge to push prematurely, allowing the cervix to continue dilating. Administering IV pain medication may not address the underlying cause of the discomfort, and pushing prematurely can lead to cervical trauma. Performing a vaginal exam is not necessary at this point as the client is already 8 centimeters dilated, and the fetal head is at 0 station.

4. What is the primary rationale for thoroughly drying the infant immediately after birth?

• A. Stimulates crying and lung expansion.
• B. Removes maternal blood from the skin surface.
• C. Reduces heat loss from evaporation.
• D. Increases blood supply to the hands and feet.

Correct answer: C

Rationale: The primary rationale for thoroughly drying the infant immediately after birth is to reduce heat loss from evaporation. This helps maintain the infant's body temperature and prevent hypothermia. Choice A (Stimulates crying and lung expansion) is incorrect because drying the infant is not primarily done to stimulate crying but rather to prevent heat loss. Choice B (Removes maternal blood from the skin surface) is incorrect as the main reason is to prevent heat loss, not to remove maternal blood. Choice D (Increases blood supply to the hands and feet) is also incorrect as drying the infant is not intended to increase blood supply but rather to regulate body temperature.

5. Twins that derive from a single zygote that has split into two are called:

• A. monozygotic (MZ) twins.
• B. fraternal twins.
• C. non-identical twins.
• D. dizygotic (DZ) twins.

Correct answer: A

Rationale: The correct answer is A: monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, occur when a single zygote splits into two embryos, leading to two genetically identical individuals. Choice B, fraternal twins, are twins that develop from two separate eggs fertilized by two different sperm cells, resulting in non-identical siblings. Choice C, non-identical twins, is not a common term used to describe this type of twinning. Choice D, dizygotic (DZ) twins, refer to twins that develop from two separate eggs fertilized by two different sperm cells, leading to non-identical twins.

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