Nursing Elites

1. What causes cystic fibrosis?

• A. Sex-linked abnormality.
• B. Abnormality in the 21st pair of chromosomes.
• C. Recessive gene.
• D. Single segment found only on the Y chromosome.

Correct answer: C

Rationale: Cystic fibrosis is a genetic disorder caused by inheriting two copies of a recessive gene, one from each parent. This means that both parents must carry at least one copy of the faulty gene for a child to inherit the condition. Choice A is incorrect because cystic fibrosis is not linked to the sex chromosomes. Choice B is incorrect as cystic fibrosis is not caused by an abnormality in the 21st pair of chromosomes but by a specific gene mutation. Choice D is also incorrect as cystic fibrosis is not related to the Y chromosome, which is specific to males.

2. A nurse is teaching about clomiphene citrate to a client who is experiencing infertility. Which of the following adverse effects should the nurse include?

• A. Tinnitus
• B. Urinary Frequency
• C. Breast Tenderness
• D. Chills

Correct answer: C

Rationale: The correct answer is C: 'Breast Tenderness.' Clomiphene citrate is known to cause breast tenderness as a common side effect due to its hormonal effects on the body. Tinnitus (choice A), which is a ringing in the ears, is not typically associated with clomiphene citrate. Urinary frequency (choice B) is not a common adverse effect of this medication. Chills (choice D) are also not commonly linked to clomiphene citrate use.

3. During a prenatal visit, for which of the following clients should the nurse auscultate the fetal heart rate?

• A. A client who has an ultrasound confirming a molar pregnancy
• B. A client who has a crown-rump length corresponding to 7 weeks gestation
• C. A client who has a positive urine pregnancy test 1 week after missed menses
• D. A client who has felt quickening for the first time

Correct answer: D

Rationale: The correct answer is D because feeling quickening typically occurs around 18-20 weeks of gestation, indicating fetal movement. This is an appropriate time to auscultate the fetal heart rate. Choice A is incorrect because a molar pregnancy is not a viable pregnancy, and auscultating the fetal heart rate in this case is not applicable. Choice B is incorrect because a crown-rump length of 7 weeks gestation is too early for fetal heart rate auscultation. Choice C is incorrect because a positive urine pregnancy test alone does not indicate the appropriate timing for fetal heart rate auscultation.

4. A 25-year-old gravida 3, para 2 client gave birth to a 9-pound, 7-ounce boy 4 hours ago after augmentation of labor with oxytocin (Pitocin). She presses her call light and asks for her nurse right away, stating 'I’m bleeding a lot.' What is the most likely cause of postpartum hemorrhage in this client?

• A. Retained placental fragments.
• B. Unrepaired vaginal lacerations.
• C. Uterine atony.
• D. Puerperal infection.

Correct answer: C

Rationale: Uterine atony is the most likely cause of bleeding 4 hours after delivery, especially after delivering a macrosomic infant and augmenting labor with oxytocin. Uterine atony is characterized by the inability of the uterine muscles to contract effectively after childbirth, leading to excessive bleeding. The other options, such as retained placental fragments (A), unrepaired vaginal lacerations (B), and puerperal infection (D), are less likely causes of postpartum hemorrhage in this scenario. Retained placental fragments can cause bleeding, but this typically presents earlier than 4 hours postpartum. Unrepaired vaginal lacerations would likely be evident sooner and not typically result in significant bleeding. Puerperal infection is not a common cause of immediate postpartum hemorrhage unless there are other signs of infection present.

5. A nurse on the labor and delivery unit is assessing four clients. Which of the following clients is a candidate for an induction of labor with misoprostol?

• A. A client who has active genital herpes
• B. A client who has gestational diabetes mellitus
• C. A client who has a previous uterine incision
• D. A client who has placenta previa

Correct answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.

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