Nursing Elites

1. _______ is a genetic disorder in which blood does not clot properly.

• A. Cystic fibrosis
• B. Hemophilia
• C. Lymphoma
• D. Huntington’s disease

Correct answer: B

Rationale: Hemophilia is a genetic disorder characterized by a deficiency in blood clotting factors, leading to prolonged bleeding. Cystic fibrosis is a genetic disorder that affects the lungs and digestive system, not blood clotting. Lymphoma is a type of cancer originating in the lymphatic system and is not related to blood clotting abnormalities. Huntington's disease is a neurodegenerative genetic disorder that affects a person's ability to move, think, and behave.

2. A client is experiencing sore nipples from breastfeeding. Which of the following actions should the nurse take?

• A. Place a snug dressing on the client’s nipple when not breastfeeding
• B. Ensure the newborn’s mouth is wide open before latching to the breast
• C. Encourage the client to limit the newborn’s feeding to 10 minutes on each breast
• D. Instruct the client to begin the feeding with the nipple that is most tender

Correct answer: B

Rationale: Ensuring the newborn's mouth is wide open before latching is crucial for achieving a proper latch, which can help reduce nipple soreness. Placing a snug dressing on the nipple when not breastfeeding (choice A) can lead to further irritation and hinder healing. Encouraging the client to limit the newborn’s feeding to 10 minutes on each breast (choice C) may not be adequate for effective feeding as infants should feed until they are satisfied. Instructing the client to begin feeding with the most tender nipple (choice D) can worsen the soreness as it may not allow the baby to feed effectively.

3. Monozygotic (MZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

4. A client in labor requests nonpharmacological pain management. Which of the following nursing actions promotes client comfort?

• A. Assisting the client into a squatting position
• B. Having the client lie in a supine position
• C. Applying fundal pressure during contractions
• D. Encouraging the client to void every 6 hours

Correct answer: A

Rationale: Assisting the client into a squatting position promotes comfort during labor. This position can help relieve pain by utilizing gravity, allowing the pelvic outlet to widen, and potentially facilitating the progress of labor. Lying in a supine position (Choice B) can hinder labor progression and increase discomfort. Applying fundal pressure (Choice C) can be inappropriate and may cause harm as it is not routinely recommended during labor. Encouraging the client to void every 6 hours (Choice D) is important for bladder management but does not directly address pain relief during labor.

5. Before meiosis, a sperm cell:

• A. contains 46 chromosomes.
• B. contains two X chromosomes.
• C. is significantly larger than an egg cell.
• D. contains both an X and a Y chromosome.

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

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