jeremy put a heavy chalk mark on the tire of his bicycle his bike tire is 27 inches in diameter when he rolled the bike the chalk left marks on the si

ATI TEAS 7

TEAS Practice Math Test

1. Jeremy put a heavy chalk mark on the tire of his bicycle. His bike tire is 27 inches in diameter. When he rolled the bike, the chalk left marks on the sidewalk. Which expression can be used to best determine the distance, in inches, the bike rolled from the first mark to the fourth mark?

A. 3(27π)
B. 4π(27)
C. (27 ÷ 3)π
D. (27 ÷ 4)π

Correct answer: A

Rationale: The distance traveled by the bike in one complete roll of the tire is equal to the circumference, which can be calculated using the formula C = πd, where d is the diameter. Given that the diameter of the bike tire is 27 inches, the circumference is obtained by multiplying the diameter by π. As the tire rolls from the first mark to the fourth mark, it completes three full rotations (one complete roll plus two more). Therefore, the total distance rolled is 3 times the circumference, which results in 3(27π). Choice A is correct. Choice B is incorrect as it incorrectly multiplies the diameter by 4π instead of multiplying the circumference by 4. Choices C and D are incorrect as they involve dividing the diameter by a number, which is not applicable in this context.

2. A gift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?

A. 56
B. 244
C. 488
D. 672

Correct answer: C

Rationale: To find the surface area of a rectangular prism, you use the formula SA = 2lw + 2wh + 2hl, where l is the length, w is the width, and h is the height. Substituting the given dimensions, the calculation would be SA = 2(14)(6) + 2(6)(8) + 2(8)(14) = 168 + 96 + 224 = 488 square inches. Therefore, 488 square inches of wrapping paper are needed to wrap the box. Choice A (56), Choice B (244), and Choice D (672) are incorrect because they do not represent the correct surface area calculation for the given box dimensions.

3. Solve the inequality for the unknown.

A. x > 5
B. x < 5
C. x >= 5
D. x <= 5

Correct answer: A

Rationale: When solving an inequality, the direction of the inequality sign changes depending on the operation performed. In this case, if the given inequality simplifies to x > 5, it means that the unknown value x must be greater than 5 for the inequality to hold true. Therefore, x > 5 is the correct solution. Option A is correct. Choices B, C, and D are incorrect because they do not correctly represent the relationship between x and 5 based on the given inequality.

4. Simplify the following expression: 6 + 7 × 3 - 4 × 2

A. -42
B. -20
C. 23
D. 20

Correct answer: B

Rationale: ollow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)): Multiply: 7 × 3 = 21, and 4 × 2 = 8 Perform addition and subtraction: 6 + 21 - 8 = 19 Thus, the simplified expression equals 19.

5. A patient requires a 30% increase in the dosage of their medication. Their current dosage is 270 mg. What will their dosage be after the increase?

A. 81 mg
B. 270 mg
C. 300 mg
D. 351 mg

Correct answer: D

Rationale: To calculate a 30% increase from the current dosage of 270 mg, first find 30% of 270, which is 81 mg. Add this 81 mg increase to the original dosage of 270 mg to get the new dosage, which is 351 mg (270 mg + 81 mg = 351 mg). Therefore, the correct answer is 351 mg. Choice A (81 mg) is incorrect because this value represents only the calculated 30% increase, not the total dosage after the increase. Choice B (270 mg) is the original dosage and does not account for the 30% increase. Choice C (300 mg) is close to the correct answer but does not consider the precise 30% increase calculation, leading to an incorrect total dosage.