Nursing Elites

1. If a tree grows an average of 4.2 inches in a day, what is the rate of change in its height per month? Assume a month is 30 days.

• A. 0.14 inches per month
• B. 4.2 inches per month
• C. 34.2 inches per month
• D. 126 inches per month

Correct answer: D

Rationale: The tree grows at an average rate of 4.2 inches per day. To find the rate of change per month, multiply the daily growth rate by the number of days in a month (30 days): 4.2 inches/day × 30 days = 126 inches per month. Therefore, the rate of change in the tree's height is 126 inches per month, making option D the correct answer. Option A is incorrect because it miscalculates the rate based on daily growth. Option B is incorrect as it doesn't account for the total days in a month. Option C is incorrect as it overestimates the monthly growth rate.

2. What is the volume of a cube with a side length of 3 cm?

• A. 9 cm³
• B. 27 cm³
• C. 18 cm³
• D. 12 cm³

Correct answer: B

Rationale: To find the volume of a cube, you cube the length of one side. In this case, the side length is 3 cm, so the volume is calculated as 3 cm * 3 cm * 3 cm = 27 cm³. Therefore, the correct answer is 27 cm³. Choice A (9 cm³), Choice C (18 cm³), and Choice D (12 cm³) are incorrect as they do not correctly calculate the volume of a cube with a side length of 3 cm.

3. What is 31% of 426?

• A. 425.69
• B. 132.06
• C. 13.7
• D. 0.07

Correct answer: B

Rationale: To find 31% of 426, multiply 0.31 by 426. This gives 0.31 × 426 = 132.06. Therefore, choice B, 132.06, is the correct answer. Choice A, 425.69, is close to the original number but is not the correct answer for the percentage calculation. Choice C, 13.7, is not the correct result for 31% of 426. Choice D, 0.07, is significantly lower than the correct answer and does not represent 31% of 426.

4. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

5. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

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