Nursing Elites

1. After meiosis, each new cell nucleus contains _____ chromosomes.

• A. 46
• B. 35
• C. 23
• D. 12

Correct answer: C

Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.

2. Daisy was always unusually short for her age. She was unable to conceive a child after marriage, and upon visiting a doctor, she was prescribed estrogen replacement therapy. Daisy is most likely suffering from:

• A. Phenylketonuria (PKU).
• B. Cystic fibrosis.
• C. Turner syndrome.
• D. Huntington’s disease (HD).

Correct answer: C

Rationale: Daisy's symptoms of short stature and infertility, along with the prescription of estrogen replacement therapy, are indicative of Turner syndrome. Turner syndrome is a genetic condition in which a female is partially or completely missing one X chromosome. This results in short stature, infertility, and other physical characteristics. Phenylketonuria (PKU) is a metabolic disorder caused by a mutation in the gene responsible for the breakdown of the amino acid phenylalanine. Cystic fibrosis is a genetic disorder affecting the respiratory and digestive systems. Huntington's disease (HD) is a neurodegenerative disorder that affects muscle coordination and leads to cognitive decline.

3. If an individual receives a recessive gene for eye color from both parents, the:

• A. gender of the child will not determine the expression of that trait.
• B. recessive trait will be expressed in the child.
• C. recessive trait will be expressed in all the offspring.
• D. recessive trait will be suppressed, and the dominant trait will not be expressed.

Correct answer: B

Rationale: When an individual inherits a recessive gene for eye color from both parents, the recessive trait will be expressed in the child. This is because having two copies of the recessive gene overrides the presence of any dominant gene. Choice A is incorrect because the expression of the trait is determined by the genetic makeup, not the gender of the child. Choice C is incorrect as the expression of the recessive trait is certain when both parents pass on the recessive gene, but it does not mean that all offspring will express the trait. Choice D is incorrect because if both parents provide a recessive gene, the dominant trait will not be expressed in the child, but it does not mean it will be suppressed; rather, the recessive trait will be expressed.

4. During a prenatal visit, for which of the following clients should the nurse auscultate the fetal heart rate?

• A. A client who has an ultrasound confirming a molar pregnancy
• B. A client who has a crown-rump length corresponding to 7 weeks gestation
• C. A client who has a positive urine pregnancy test 1 week after missed menses
• D. A client who has felt quickening for the first time

Correct answer: D

Rationale: The correct answer is D because feeling quickening typically occurs around 18-20 weeks of gestation, indicating fetal movement. This is an appropriate time to auscultate the fetal heart rate. Choice A is incorrect because a molar pregnancy is not a viable pregnancy, and auscultating the fetal heart rate in this case is not applicable. Choice B is incorrect because a crown-rump length of 7 weeks gestation is too early for fetal heart rate auscultation. Choice C is incorrect because a positive urine pregnancy test alone does not indicate the appropriate timing for fetal heart rate auscultation.

5. A mother spontaneously delivers a newborn infant in the taxicab while on the way to the hospital. The emergency room nurse reported the mother has active herpes (HSV II) lesions on the vulva. Which intervention should the nurse implement first when admitting the neonate to the nursery?

• A. Document the newborn's temperature on the flow sheet.
• B. Place the newborn in the isolation area of the nursery.
• C. Obtain a blood specimen for a serum glucose level.
• D. Administer the vitamin K injection.

Correct answer: B

Rationale: Newborns exposed to active herpes lesions are at high risk for neonatal herpes, which can be severe. Placing the newborn in isolation is crucial as it helps prevent the spread of the virus and allows for close monitoring. Documenting the newborn's temperature, obtaining a blood specimen for a serum glucose level, and administering the vitamin K injection are important interventions but are not the priority when dealing with a potential infectious risk like neonatal herpes.

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