a nurse is preparing to administer methylergonovine 02 mg orally to a client who is 2 hr postpartum and has a boggy uterus for which of the following
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Maternity HESI Practice Questions

1. A client is preparing to administer methylergonovine 0.2 mg orally to a client who is 2 hr postpartum and has a boggy uterus. For which of the following assessment findings should the nurse withhold the medication?

Correct answer: A

Rationale: The correct answer is A. Methylergonovine can increase blood pressure, so it should be withheld if the client has hypertension. A blood pressure reading of 142/92 mm Hg indicates hypertension and is a contraindication for administering methylergonovine. Choices B, C, and D are within normal limits and not contraindications for administering this medication. Urine output, pulse rate, and respiratory rate are not factors that determine the appropriateness of administering methylergonovine in this situation.

2. Is a low sperm count or lack of sperm the most common infertility problem in men?

Correct answer: A

Rationale: A low sperm count or lack of sperm is indeed one of the most common causes of infertility in men. Factors such as hormonal imbalances, genetic issues, reproductive anatomy problems, and lifestyle factors can also contribute to male infertility. Choice B is incorrect because a low sperm count is a prevalent issue among men facing infertility, making it a common problem. Choices C and D are incorrect as they do not accurately reflect the prevalence of low sperm count as a cause of infertility in men.

3. Which information regarding the care of antepartum women with cardiac conditions is most important for the nurse to understand?

Correct answer: B

Rationale: Class II cardiac disease is symptomatic with ordinary activity. Women in this category need to avoid heavy exertion and limit regular activities as symptoms dictate. Stress is greatest between weeks 28 and 32 of gestation, when hemodynamic changes reach their maximum. Class III cardiac disease is symptomatic with less-than-ordinary activity. These women need bed rest most of the day and face the possibility of hospitalization near term. Class I cardiac disease is asymptomatic at normal levels of activity. These women can perform limited normal activities with discretion, although they still need a good amount of sleep.

4. Twins that derive from a single zygote that has split into two are called:

Correct answer: A

Rationale: The correct answer is A: monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, occur when a single zygote splits into two embryos, leading to two genetically identical individuals. Choice B, fraternal twins, are twins that develop from two separate eggs fertilized by two different sperm cells, resulting in non-identical siblings. Choice C, non-identical twins, is not a common term used to describe this type of twinning. Choice D, dizygotic (DZ) twins, refer to twins that develop from two separate eggs fertilized by two different sperm cells, leading to non-identical twins.

5. After meiosis, each new cell nucleus contains _____ chromosomes.

Correct answer: C

Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.

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