Nursing Elites

1. A nurse is caring for a newborn who is 6 hours old and has a bedside glucometer reading of 65 mg/dL. The newborn’s mother has type 2 diabetes mellitus. Which of the following actions should the nurse take?

• A. Obtain a blood sample for a serum glucose level
• B. Feed the newborn immediately
• C. Administer 50 mL of dextrose solution IV
• D. Reassess the blood glucose level prior to the next feeding

Correct answer: D

Rationale: A bedside glucometer reading of 65 mg/dL is within the normal range for a newborn. Reassessing the blood glucose level prior to the next feeding ensures ongoing monitoring without unnecessary intervention. Obtaining a blood sample for a serum glucose level (Choice A) is not necessary as the initial reading is normal. Feeding the newborn immediately (Choice B) may not be indicated and could lead to unnecessary interventions. Administering dextrose solution IV (Choice C) is not warranted as the glucose level is within the normal range and does not require immediate correction.

2. A newborn is 1 hour old with a respiratory rate of 50/min, a heart rate of 130/min, and an axillary temperature of 36.1°C (97°F). Which of the following actions should be taken?

• A. Give the newborn a warm bath.
• B. Apply a cap to the newborn's head.
• C. Reposition the newborn.
• D. Obtain an oxygen saturation level.

Correct answer: B

Rationale: Applying a cap to the newborn's head is the correct action in this scenario. Newborns are at risk of heat loss due to their high surface area to volume ratio, and maintaining their body temperature is crucial to prevent hypothermia. Giving a warm bath can further increase heat loss and is not recommended. Repositioning the newborn may not address the primary concern of temperature regulation. While monitoring oxygen saturation is important, addressing thermal regulation takes precedence in this situation.

3. After a mother was diagnosed with gonorrhea immediately after delivery, what is an important goal of the nurse when providing care for her baby?

• A. Prevent the development of ophthalmia neonatorum.
• B. Lubricate the eyes.
• C. Prevent the development of infection.
• D. Teach about the risks of breastfeeding with gonorrhea.

Correct answer: A

Rationale: The correct answer is A: Prevent the development of ophthalmia neonatorum. When a mother has gonorrhea, the baby can be infected during delivery, leading to ophthalmia neonatorum, which can cause permanent blindness. Therefore, it is crucial for the nurse to prevent this condition by treating the baby's eyes with an antibiotic prophylactically after birth. Choice B, lubricating the eyes, is not the primary goal in this situation as preventing infection takes precedence. Choice C, preventing the development of infection, is too broad and does not specifically address the potential complication of ophthalmia neonatorum. Choice D, teaching about the risks of breastfeeding with gonorrhea, is important but not the immediate goal in this scenario where preventing ophthalmia neonatorum and potential blindness is the priority.

4. A client is preparing to administer methylergonovine 0.2 mg orally to a client who is 2 hr postpartum and has a boggy uterus. For which of the following assessment findings should the nurse withhold the medication?

• A. Blood pressure 142/92 mm Hg
• B. Urine output 100 mL in 1 hr
• C. Pulse 58/min
• D. Respiratory rate 14/min

Correct answer: A

Rationale: The correct answer is A. Methylergonovine can increase blood pressure, so it should be withheld if the client has hypertension. A blood pressure reading of 142/92 mm Hg indicates hypertension and is a contraindication for administering methylergonovine. Choices B, C, and D are within normal limits and not contraindications for administering this medication. Urine output, pulse rate, and respiratory rate are not factors that determine the appropriateness of administering methylergonovine in this situation.

5. After meiosis, each new cell nucleus contains _____ chromosomes.

• A. 46
• B. 35
• C. 23
• D. 12

Correct answer: C

Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.

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